FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of... Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Seite 181von Euclid - 1765 - 464 SeitenVollansicht - Über dieses Buch
| Euclides - 1846
...each to each, and therefore FH is equal to FK : And in like manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK ; Therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another, and the circle described from the centre... | |
| Royal Military Academy, Woolwich - 1853
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated that FL, **FM, FG are each of them equal to FH, or FK ; Therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
| Euclides - 1853 - 147 Seiten
...perpendicular fh is equal to the perpendicular f k. In the same manner, it may be demonstrated that ft **fm, fg are each of them equal to fh, or fk : therefore the five** straight lines fg, fh, f fc f 1, fm are equal to one another : wherefore the circle described from... | |
| Euclides - 1853
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that 8. FL, **FM, FG, are each of them equal to FH or FK: therefore** 9. The five straight lines FG, FH, FK, FL, FM, are equal to one another; wherefore the circle described... | |
| Euclides - 1855
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may be shown that FL, FM, and **FG, are each of them equal to FH, or FK. Therefore the five** straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
| Robert Potts - 1860 - 361 Seiten
...perpendicular FH is equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK: therefore the five** straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
| Euclides - 1860
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, and **FG are each of them equal to FH or FK ; therefore the five** straight lines FG, FH, FK, FL, and FM are equal to one another ; wherefore the circle described from... | |
| Euclides - 1862
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, **FM, FG, are each of them equal to FH or FK ; therefore the five** straight linos FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... | |
| Euclides - 1863
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may shown that FL, FM, and **FG are each of them equal to FH, or FK. Therefore the five** straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
| Euclides - 1864
...perpendicular FHis equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK: therefore the five** straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
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