FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of... Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Seite 183von Euclid - 1765 - 464 SeitenVollansicht - Über dieses Buch
| Euclides - 1826 - 226 Seiten
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, **FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore** with centre F and distance any one of them FG, FH, FK, FL, FM, the circle described will both pass... | |
| Euclid - 1826 - 234 Seiten
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, **FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore** with centre F and distance any one of them FO, FH, FK, FL, FM, the circle described will both pass... | |
| Robert Simson - 1827 - 546 Seiten
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK : therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
| Euclid - 1835 - 540 Seiten
...perpendicular FH is equal to the perpendicular FK : In the same manner, it may be demonstrated, that FL, **FM, FG are each of them equal to FH or FK : Therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the circle described from the... | |
| Andrew Bell - 1837 - 290 Seiten
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, **FM, FG, are each of them equal to FH or FK ; therefore the five** straight lines FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... | |
| Euclides - 1841 - 378 Seiten
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, **FM, FG are each of them equal to FH or FK: therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another: wherefore the circle described from the... | |
| John Playfair - 1842 - 332 Seiten
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK ; therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
| Euclides - 1845 - 546 Seiten
...perpendicular FH is equal to the perpendicular FA": in the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK: therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
| Euclid - 1845 - 218 Seiten
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK ; Therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another; wherefore the circle described from the... | |
| Euclides - 1846 - 292 Seiten
...each to each, and therefore FH is equal to FK : And in like manner it may be demonstrated, that FL, **FM, FG are each of them equal to FH, or FK ; Therefore the five** straight lines FG, FH, FK, FL, FM are equal to one another, and the circle described from the centre... | |
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