 FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...  Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Seite 181von Euclid - 1765 - 464 SeitenVollansicht - Über dieses Buch
 | Euclides - 1826
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore with centre F and distance any one of them FG, FH, FK, FL, FM, the circle described will both pass... | |
 | Euclid - 1826 - 180 Seiten
...manner it may be demonstrated that each of the sides FL, FM, FG, is equal to each of the sides FH, FK ; therefore the five right lines FG, FH, FK, FL, FM, are equal to one another. Wherefore with centre F and distance any one of them FO, FH, FK, FL, FM, the circle described will both pass... | |
 | Robert Simson - 1827 - 513 Seiten
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
 | Euclid - 1835 - 513 Seiten
...perpendicular FH is equal to the perpendicular FK : In the same manner, it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK : Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the circle described from the... | |
 | Andrew Bell - 1837 - 240 Seiten
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, FG, are each of them equal to FH or FK ; therefore the five straight lines FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... | |
 | Euclides - 1841 - 351 Seiten
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, FM, FG are each of them equal to FH or FK: therefore the five straight lines FG, FH, FK, FL, FM are equal to one another: wherefore the circle described from the... | |
 | John Playfair - 1842 - 317 Seiten
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
 | Euclides - 1845
...perpendicular FH is equal to the perpendicular FA": in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
 | Euclid - 1845 - 199 Seiten
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another; wherefore the circle described from the... | |
 | John Playfair - 1846 - 317 Seiten
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
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