 | John Daniel Runkle - 1860 - 460 Seiten
...figure must be aliquot parts of the circle or of four right angles. All the angles of any such figure are equal to twice as many right angles as the figure has sides minus four right angles, or if « be the number of sides, the sum of all the angles is (2 n —... | |
 | William Schofield Binns - 1861 - 238 Seiten
...let the required polygon be a pentagon. From Euc. I., 32, Cor. 1, "All the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides." From this corollary, we can deduce a formula for finding the angle of any polygon. Let x equal... | |
 | Elias Loomis - 1861 - 244 Seiten
...there are sides of the polygon BCDEF. Also, the anGEOMETRY. gles of the polygon, together with lour right angles, are equal to twice as many right angles as the figure has sides (Prop. XXVIII., BI) ; hence all the angles of the triangles are equal to all the angles of the... | |
 | Euclides - 1862 - 172 Seiten
...all the triangles, are equal to four right angles, (i. 15, cor. 2) therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Cor. 2. Att the exterior angles of any rectilineal figure are together equal to four right angles.... | |
 | Euclides - 1862 - 140 Seiten
...with its adjacent exterior angle ABD, are equal to two right angles. (I. 13.) angles of the figure, are equal to twice as many right angles as the figure has sides. 3. But all the interior angles, together with four right angles, are equal to twice as many... | |
 | University of Oxford - 1863 - 316 Seiten
...fall on it from the opposite angle, and the acute angle. 4. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 5. Describe a parallelogram equal to a given rectilineal figure, and having an angle equal to... | |
 | Euclides - 1863 - 122 Seiten
...point F within the Cor. 1.—All the interior angles (ABC, BCD, &c.) of any rectilineal figure (ABCDE) together with four right angles are equal to twice as many right angles as the figure has sides. ., figure to each of its angles. \ Because the three interior angles of a triangle are equal... | |
 | Henry S. Merrett - 1863 - 428 Seiten
...sides. It has been proved by the foregoing corollary that all the interior angles, together with the four right angles, are equal to twice as many right angles as the figure has sides. Therefore all the interior angles, together with all the exterior angles, are equal to all the... | |
 | Henry S. Merrett - 1863 - 476 Seiten
...sides. It has been proved by the foregoing corollary that all the interior angles, together with the four right angles, are equal to twice as many right angles as the figure has sides. Therefore all the interior angles, together with all the exterior angles, are equal to all the... | |
 | Euclides - 1864 - 448 Seiten
...Wherefore, if a side of any triangle be produced, &c. QED COR. 1. All the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. D For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides,... | |
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Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
