 | Dennis M'Curdy - 1846 - 166 Seiten
...any angle with AB. In AC take a point D, and make AC the same multiple of AD that AB is of the part to be cut off from it: join BC, and draw DE parallel to it ; AE is the part required. Because ED is parallel to BC, a side of the triangle ABC (a), CD : DA :... | |
 | Royal Military Academy, Woolwich - 1853 - 400 Seiten
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so is... | |
 | Euclides - 1853 - 176 Seiten
...making any angle with ab; and in a С take any point d, and take a С the same multiple of ad, that a Ь is of the part which is to be cut off from it : join, b С, and draw de parallel to it : then ae is the part required to be cut off. Because ed is parallel... | |
 | Euclides - 1855 - 230 Seiten
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...draw DE parallel to it : then AE is the part required tobecut of. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle ABC ; as... | |
 | John Playfair - 1855 - 334 Seiten
...and in AC take any point 1), and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC, and dniw DE parallel to it: then AK is the part required to be cut off. triangle ABC, viz. to BC, CD :... | |
 | Euclides - 1860 - 288 Seiten
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD that AB is of the part which is to...to it; then AE is the part required to be cut off. (Dem.) Because ED is parallel to one of the sides of the triangle ABC, namely, to BC ; CD is to DA... | |
 | Eucleides - 1860 - 396 Seiten
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...to it .then AE is the part required to be cut off. VI. 2. 6) V. 18. v. D. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle... | |
 | Robert Potts - 1860 - 380 Seiten
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclides - 1863 - 122 Seiten
...angle BAC with AB. In AC take any point D, and make AC the same multiple of AD that AB is of the part to be cut off from it. Join BC, and draw DE parallel to CB. The A part AE is the part required to be cut off from AB. PEOP. IX. (PEOELEM.)—From a gicen straight... | |
 | Euclides - 1864 - 448 Seiten
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
