The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected; and Some of Euclid's Demonstrations are Restored. Also the Book of Euclid's Data, in Like Manner Corrected. the first six books, together with the eleventh and twelfthJ. Nourse, London, and J. Balfour, Edinburgh, 1775 - 520 Seiten |
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Seite 39
... third angle of the one to the third angle of the other " , viz . b 26 , I , the fide AB to the fide CD , and AC to BD , and the angle BAC equal to the angle BDC : And because the angle ABC is equal to the angle BCD , and the angle CBD ...
... third angle of the one to the third angle of the other " , viz . b 26 , I , the fide AB to the fide CD , and AC to BD , and the angle BAC equal to the angle BDC : And because the angle ABC is equal to the angle BCD , and the angle CBD ...
Seite 110
... third angle . Take any straight line AB , and divide it in the point C , fo that the rectangle AB , BC be equal to the fquare of CA ; and from the center A , at the diftance AB , defcribe the circle BDE , in which place the ftraight ...
... third angle . Take any straight line AB , and divide it in the point C , fo that the rectangle AB , BC be equal to the fquare of CA ; and from the center A , at the diftance AB , defcribe the circle BDE , in which place the ftraight ...
Seite 111
... third angle . Which was to be done . T PROP . XI . PROB . O infcribe an equilateral and equiangular pentagon in a given circle . Let ABCDE be the given circle ; it is required to infcribe an equilateral and equiangular pentagon in the ...
... third angle . Which was to be done . T PROP . XI . PROB . O infcribe an equilateral and equiangular pentagon in a given circle . Let ABCDE be the given circle ; it is required to infcribe an equilateral and equiangular pentagon in the ...
Seite 113
... third g 26. 1 . angle to the third angle : Therefore the ftraight line KC is equal to CL , and the angle FKC to the angle FLC : And because KC is equal to CL , KL is double of KC : In the fame manner , it may be fhewn that HK is double ...
... third g 26. 1 . angle to the third angle : Therefore the ftraight line KC is equal to CL , and the angle FKC to the angle FLC : And because KC is equal to CL , KL is double of KC : In the fame manner , it may be fhewn that HK is double ...
Seite 116
... third part of two right angles : In the fame manner it may be demonftrated that the angle DGC is alfo the third part of two right angles : And because the ftraight line GČ makes with EB the adjacent angles EGC , CGB equal to two right ...
... third part of two right angles : In the fame manner it may be demonftrated that the angle DGC is alfo the third part of two right angles : And because the ftraight line GČ makes with EB the adjacent angles EGC , CGB equal to two right ...
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alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle bifected Book XI cafe circle ABCD circumference cone confequently cylinder defcribed demonftrated diameter drawn equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fhall fhewn fide BC fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife line BC oppofite parallel parallelepipeds parallelogram perpendicular polygon prifm propofition proportionals pyramid Q. E. D. PROP rectangle contained rectilineal figure right angles thefe THEOR theſe triangle ABC vertex wherefore
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Seite 32 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Seite 165 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF.
Seite 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Seite 10 - When several angles are at one point B, any ' one of them is expressed by three letters, of which ' the letter that is at the vertex of the angle, that is, at ' the point in which the straight lines that contain the ' angle meet one another, is put between the other two ' letters, and one of these two is...
Seite 55 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Seite 32 - ... then shall the other sides be equal, each to each; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, BCA equal to the angles DEF, EFD, viz.
Seite 45 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Seite 211 - AB shall be at right angles to the plane CK. Let any plane DE pass through AB, and let CE be the common section of the planes DE, CK ; take any point F in CE, from which draw FG in the plane DE at right D angles to CE ; and because AB is , perpendicular to the plane CK, therefore it is also perpendicular to every straight line in that plane meeting it (3.
Seite 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 304 - Thus, if B be the extremity of the line AB, or the common extremity of the two lines AB, KB, this extremity is called a point, and has no length : For if it have any, this length must either be part of the length of the line AB, or of the line KB.