The Elements of Euclid, containing the first six books, with a selection of geometrical problems. To which is added the parts of the eleventh and twelfth books which are usually read at the universities. By J. Martin1874 |
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Seite 20
... join CF. Then CF , drawn from the point C , shall be at right angles to AB . Proof . Because DC is equal to EC , and FC is common to the two triangles DCF , ECF , and 1. The two sides DC , CF are equal to the two sides EC , CF , each to ...
... join CF. Then CF , drawn from the point C , shall be at right angles to AB . Proof . Because DC is equal to EC , and FC is common to the two triangles DCF , ECF , and 1. The two sides DC , CF are equal to the two sides EC , CF , each to ...
Seite 22
... join CF , CH , CG . Then the straight line CH drawn from the given point C , shall be perpendicular to the given straight line AB . Proof . Because FH is equal to HG ( constr . ) , and HC is common to the two triangles FHC , GHC ; and ...
... join CF , CH , CG . Then the straight line CH drawn from the given point C , shall be perpendicular to the given straight line AB . Proof . Because FH is equal to HG ( constr . ) , and HC is common to the two triangles FHC , GHC ; and ...
Seite 26
... join BE ; produce BE to F , making EF equal to BE ( I. 3 ) and join FC . Demonstration . Because AE is equal to EC , and BE to EF ( constr . ) , and 1. The two sides AE , EB are equal to the two CE , EF , each to each , in the triangles ...
... join BE ; produce BE to F , making EF equal to BE ( I. 3 ) and join FC . Demonstration . Because AE is equal to EC , and BE to EF ( constr . ) , and 1. The two sides AE , EB are equal to the two CE , EF , each to each , in the triangles ...
Seite 27
... be greater than the angle ACB . Construction . Since the side AC is greater than the side AB ( hyp . ) , make AD equal to AB ( I. 3 ) and join BD . Demonstration . Then , because AD is equal to AB BOOK I. - PROP . XVII . 27.
... be greater than the angle ACB . Construction . Since the side AC is greater than the side AB ( hyp . ) , make AD equal to AB ( I. 3 ) and join BD . Demonstration . Then , because AD is equal to AB BOOK I. - PROP . XVII . 27.
Seite 29
... join DC . Demonstration . Then because AD is equal to AC ( constr . ) , therefore 1. The angle ACD is equal to the angle ADC ( I. 5 ) , but the angle BCD is greater than the angle ACD ( Ax . 9 ) , there- fore also 2. The angle BCD is ...
... join DC . Demonstration . Then because AD is equal to AC ( constr . ) , therefore 1. The angle ACD is equal to the angle ADC ( I. 5 ) , but the angle BCD is greater than the angle ACD ( Ax . 9 ) , there- fore also 2. The angle BCD is ...
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The Elements of Euclid, Containing the First Six Books, with a Selection of ... Euclides Keine Leseprobe verfügbar - 2016 |
Häufige Begriffe und Wortgruppen
AC is equal adjacent angles angle ABC angle ACB angle BAC angle BCD angle DEF angle EDF angle equal base BC bisected centre circle ABC circumference constr Demonstration diameter double equal angles equal to F equiangular equilateral triangle equimultiples ex æquali exterior angle fourth given circle given point given straight line gnomon greater ratio inscribed less Let ABC Let the straight linear units meet multiple opposite angle parallel to BC parallelogram perpendicular plane polygon produced proportionals Q.E.D. PROPOSITION quadrilateral rectangle contained remaining angle right angles segment semicircle similar square on AC straight line AB straight line BC straight line drawn three straight lines tiple touches the circle triangle ABC triangle DEF twice the rectangle wherefore
Beliebte Passagen
Seite 1 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Seite 6 - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles...
Seite 232 - If two triangles, which have two sides of the one proportional to two sides of the other, be joined at one angle, so as to have their homologous sides parallel to one another, the remaining sides shall be in a straight line. Let...
Seite 112 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Seite 209 - ... triangles which have one angle in the one equal to one angle in the other, and their sides about the equal angles reciprocally proportional, are equal to one another.
Seite 269 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Seite 199 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Seite 23 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.
Seite 63 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...
Seite 32 - ... twice as many right angles as the figure has sides ; therefore all the angles of the figure together with four right angles, are equal to twice as many right angles as the figure has sides.