Books 10-13 and appendixThe University Press, 1908 |
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Ergebnisse 6-10 von 100
Seite 269
... base and opposite . its Heron goes on to explain that , if the face opposite to the base reduces to a straight line , and a solid is formed by connecting the base to its extremities by straight lines , as in the other case , the ...
... base and opposite . its Heron goes on to explain that , if the face opposite to the base reduces to a straight line , and a solid is formed by connecting the base to its extremities by straight lines , as in the other case , the ...
Seite 270
... base of the cone lying between the said circle and the fixed point , and the axis is defined as the straight line drawn from the fixed point , or the apex , to the centre of the circle forming the base . Apollonius goes on to say that ...
... base of the cone lying between the said circle and the fixed point , and the axis is defined as the straight line drawn from the fixed point , or the apex , to the centre of the circle forming the base . Apollonius goes on to say that ...
Seite 278
... base CB , and the triangle AED will be equal to the triangle CEB ; [ 1.4 ] so that the angle DAE is also equal to ... base FA is equal to the base FB . [ 1. 4 ] For the same reason FC is also equal to FD . And , since AD is equal to CB ...
... base CB , and the triangle AED will be equal to the triangle CEB ; [ 1.4 ] so that the angle DAE is also equal to ... base FA is equal to the base FB . [ 1. 4 ] For the same reason FC is also equal to FD . And , since AD is equal to CB ...
Seite 279
... base FG is equal to the base FH ; therefore the angle GEF is equal to the angle HEF . Therefore each of the angles GEF , HEF is right . Therefore FE is at right angles to GH drawn at ran through E. Similarly we can prove that FE will ...
... base FG is equal to the base FH ; therefore the angle GEF is equal to the angle HEF . Therefore each of the angles GEF , HEF is right . Therefore FE is at right angles to GH drawn at ran through E. Similarly we can prove that FE will ...
Seite 283
... base AD is equal to the base BE . And , since AB is equal to DE , while AD is also equal to BE , the two sides AB , BE are equal to the two sides and AE is their common base ; therefore the angle ABE is equal to the angle EL BD , DC ...
... base AD is equal to the base BE . And , since AB is equal to DE , while AD is also equal to BE , the two sides AB , BE are equal to the two sides and AE is their common base ; therefore the angle ABE is equal to the angle EL BD , DC ...
Häufige Begriffe und Wortgruppen
area a medial base bimedial binomial straight line bisected circle ABCD commensurable in length commensurable in square cone cut in extreme cylinder decagon diameter dihedral angle dodecahedron equal equilateral Euclid extreme and mean greater segment height icosahedron inscribed irrational straight line kp² Lemma let the square magnitudes mean ratio medial area medial straight line medial whole parallel parallelepipedal solids parallelogram pentagon perpendicular plane of reference polygon prism Proclus PROPOSITION proved rational and incommensurable rational area rational straight line rectangle AC rectangle contained right angles second apotome side Similarly solid angle sphere square number square on AB squares on AC straight lines commensurable surable triangle twice the rectangle vertex whence
Beliebte Passagen
Seite 310 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 372 - Two unequal magnitudes being set out, if from the greater there be subtracted a magnitude greater than its half, and from that which is left a magnitude greater than its half, and if this process be repeated continually, there will be left some magnitude which will be less than the lesser magnitude set out?
Seite 260 - The inclination of a plane to a plane is the acute angle contained by two straight lines drawn from any the...
Seite 295 - BAE; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but one perpendicular to that plane ; for, if there could be two, they would be parallel (6. PI.) to one another, which is absurd. Therefore, from the same point, &c.
Seite 279 - AB, CD. In like manner, it may be proved, that FE makes right angles with every straight line which meets it in that plane. But a straight line is at right angles to a plane when it makes right angles with every straight line which meets it in that plane : (xi. def. 3.) therefore EF is at right angles to the plane in which are AB, CD. Wherefore, if a straight line, &c.
Seite 389 - The upper end of the frustum of a pyramid or cone is called the upper base...
Seite 324 - AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH to CF ; the two straight lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another...
Seite 294 - To erect a straight line at right angles to a given plane, from a point given in the plane. Let A be the point given in the plane.
Seite 304 - And because the plane AB is perpendicular to the third plane, and DE is drawn in the plane AB at right angles to AD their common section...
Seite 345 - N. equiangular to one another, each to each, that is, of which the folid angles are equal, each to each ; have to one another the ratio which is the fame with the ratio compounded of the ratios of their fides.