Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J. Pryde. [With] Key1860 |
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Seite 219
... sine of an arc is a line drawn from one of its extremities , perpendicular to the radius passing through its other extremity . 4. The tangent of an arc is a line touching it at one extremity , and limited by the radius produced through ...
... sine of an arc is a line drawn from one of its extremities , perpendicular to the radius passing through its other extremity . 4. The tangent of an arc is a line touching it at one extremity , and limited by the radius produced through ...
Seite 220
... sine and the extremity of the arc . 7. The supplemental versed sine , or suversed sine , is the difference between the versed sine and the diameter . 8. The sine , tangent , secant , & c . , of the complement of an arc , are concisely ...
... sine and the extremity of the arc . 7. The supplemental versed sine , or suversed sine , is the difference between the versed sine and the diameter . 8. The sine , tangent , secant , & c . , of the complement of an arc , are concisely ...
Seite 221
... sine to the cosine . For in the similar triangles OAF and OEB , BE : EO , or tan . A : R = sin . A : cos . A. 8. The tangent is to the secant as the radius to the cosecant . For in the similar triangles FAO and OCH , CO : OH , or tan ...
... sine to the cosine . For in the similar triangles OAF and OEB , BE : EO , or tan . A : R = sin . A : cos . A. 8. The tangent is to the secant as the radius to the cosecant . For in the similar triangles FAO and OCH , CO : OH , or tan ...
Seite 222
Euclides James Pryde. 16. The sine , tangent , and secant of an arc , are the same as those of that arc increased by ... sine and cosecant are reciprocals . 6. Cos . A. sec . A = 1 , 1 sec . A = cos . A 1 therefore cos . A = sec . A ' or ...
Euclides James Pryde. 16. The sine , tangent , and secant of an arc , are the same as those of that arc increased by ... sine and cosecant are reciprocals . 6. Cos . A. sec . A = 1 , 1 sec . A = cos . A 1 therefore cos . A = sec . A ' or ...
Seite 223
... sine of A ; but the angle at C is the complement of A , therefore BC is the cosine of C. By A C E BD making C the centre , it may be similarly proved that AB is the sine of C , and therefore the cosine of A. PROPOSITION II . THEOREM ...
... sine of A ; but the angle at C is the complement of A , therefore BC is the cosine of C. By A C E BD making C the centre , it may be similarly proved that AB is the sine of C , and therefore the cosine of A. PROPOSITION II . THEOREM ...
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Euclid's Elements of Plane Geometry [Book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde Keine Leseprobe verfügbar - 2023 |
Euclid's Elements of Plane Geometry [book 1-6] Explicitly Enunciated, by J ... Euclides,James Pryde Keine Leseprobe verfügbar - 2018 |
Häufige Begriffe und Wortgruppen
ABCD adjacent angles angle ABC angle ACB angle BAC apothem base BC BC is equal bisected centre Chambers's chord circle ABC circumference Const cosec cosine described diameter divided double draw equal angles equal to twice equiangular equilateral equilateral polygon equimultiples exterior angle fore given line given point given straight line gnomon greater hence hypotenuse inscribed isosceles triangle less line drawn multiple number of sides opposite angle parallel parallelogram perimeter perpendicular polygon produced proportional PROPOSITION prove radius ratio rectangle contained rectilineal figure regular polygon remaining angle right angles right-angled triangle segment semiperimeter shewn similar sine square on AC straight line AC tangent THEOREM third touches the circle triangle ABC triangle DEF twice the rectangle vertical angle wherefore
Beliebte Passagen
Seite 23 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Seite 52 - If a straight line be bisected, and produced to any point; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square of half the line bisected, is equal to the square of the straight line which is made up of the half and the part produced.
Seite 51 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Seite 53 - If a straight line be divided into any two parts, the squares of the whole line, and of one of the parts, are equal to twice the rectangle contained by the whole and that part, together with the square of the other part. Let the straight line AB be divided into any two parts in the point C ; the squares of AB, BC are equal to twice the rectangle AB, BC...
Seite 3 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Seite 29 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 117 - And the same thing is to be understood when it is more briefly expressed by saying, a has to d the ratio compounded of the ratios of e to f, g to h, and k to l. In like manner, the same things being supposed, if m has to n the same ratio which a has to d ', then, for shortness...
Seite 13 - Upon the same base, and on the same side of it, there cannot be two triangles that have their sides which are terminated in one extremity of the base equal to one another, and likewise those which are terminated in the other extremity.
Seite 159 - From the point A draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so is (2.
Seite 60 - CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i.