The geometry, by T. S. Davies. Conic sections, by Stephen FenwickJ. Weale, 1853 |
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Seite 4
... draw the straight lines ( 1 Post . ) CA , CB , to the points A , B : ABC shall be an equilateral triangle . D C ... draw a straight line equal to a given straight line . Let A be the given point , and BC the given straight line ; it is ...
... draw the straight lines ( 1 Post . ) CA , CB , to the points A , B : ABC shall be an equilateral triangle . D C ... draw a straight line equal to a given straight line . Let A be the given point , and BC the given straight line ; it is ...
Seite 10
... draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ( 10 Def . ) to the angle EBA ; in the same manner , because ABD is a straight line , the angle DBE is equal to the angle EBA ; wherefore ( 1 Ax ...
... draw BE at right angles to AB ; and because ABC is a straight line , the angle CBE is equal ( 10 Def . ) to the angle EBA ; in the same manner , because ABD is a straight line , the angle DBE is equal to the angle EBA ; wherefore ( 1 Ax ...
Seite 20
... draw a straight line through a given point parallel to a given straight line . Let A be the given point , and BC the given straight line ; it is required to draw a straight line through the point A , parallel to the straight line BC ...
... draw a straight line through a given point parallel to a given straight line . Let A be the given point , and BC the given straight line ; it is required to draw a straight line through the point A , parallel to the straight line BC ...
Seite 24
... draw BG parallel ( 31. 1. ) to CA , and through F draw FH parallel to ED : then each of the figures GBCA , DEFH , is a ( Def . 34. 1. ) parallelogram ; and they are equal ( 36. 1. ) to one another , because they are upon equal bases BC ...
... draw BG parallel ( 31. 1. ) to CA , and through F draw FH parallel to ED : then each of the figures GBCA , DEFH , is a ( Def . 34. 1. ) parallelogram ; and they are equal ( 36. 1. ) to one another , because they are upon equal bases BC ...
Seite 25
... draw ( 31.1 . ) AG parallel to EC , and through C draw CG parallel to EF : therefore FECG is a ( Def . 34. 1. ) parallelogram . And because BE is equal ( Constr . ) to EC , the triangle ABE is likewise equal ( 38. 1. ) to B E the ...
... draw ( 31.1 . ) AG parallel to EC , and through C draw CG parallel to EF : therefore FECG is a ( Def . 34. 1. ) parallelogram . And because BE is equal ( Constr . ) to EC , the triangle ABE is likewise equal ( 38. 1. ) to B E the ...
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ABC is equal ABCD adjacent angles angle ABC angle BAC axis bisected centre circle ABC circumference coincide cone construction coordinate planes described Descriptive Geometry diameter dicular dihedral angles draw edges ellipse equal angles equiangular equimultiples given line given point given straight line greater hence horizontal hyperbola inclination intersection join less Let ABC Let the plane line BC lines drawn magnitudes meet multiple orthograph parabola parallel planes parallelogram parallelopiped perpen perpendicular perpendicular to MN plane MN plane of projection plane parallel plane PQ prisms profile angles profile plane projecting plane Prop Q. E. D. PROPOSITION ratio rectangle rectangle contained rectilineal figure remaining angle respectively right angles SCHOLIUM segment sides six right sphere spherical angle tangent THEOR trace triangle ABC trihedral vertex Whence Wherefore