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" AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH to CF ; the two straight lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another... "
Books 10-13 and appendix - Seite 324
von Euclid - 1908
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1806 - 311 Seiten
...may be proved that each of the figures CE, FG, GB, BF, AE is a parallelogram. Join AH, DF. Because AB is parallel to DC, and BH to CF, the two straight lines AB, BH, which meet each other, are parallel to DC, ($F, which meet each other ; therefore the angle ABH is equal to the...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - 1806 - 518 Seiten
...CE, FG, GB, BF, AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH, toCF; the two straight lines AB, BH which meet one another, are parallel to DC and CF which meet one another, and are not in the same plane with the other two; wherefore they...
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The Elements of Euclid; viz. the first six books, together with the eleventh ...

Euclides - 1814 - 558 Seiten
...parallelograms. that each of the figures CE, FG, GB, BF, AE, is a parallelogram: Join AH, DF; and because AB is parallel to DC, and BH to CF; the two straight...lines AB, BH, which meet one another, are parallel to DC and CF, which meet c same plane with the other two: wherefore they contain * 10.1i. equal angles,...
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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclides - 1816 - 528 Seiten
...be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram : Join AH, DF; and because AB is parallel to DC, and BH to CF; the two straight...lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another, and are not in the same plane with the other two : wherefore they...
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Elements of Geometry: Containing the First Six Books of Euclid: With a ...

John Playfair - 1819 - 317 Seiten
...be proved that each of the figures CE, FG, GB, BF, AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH to CF ; the two straight...lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another ; wherefore, though the first two are not in the same plane with...
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The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh ...

Euclid, Robert Simson - 1821 - 514 Seiten
...figures CE, FG, GB, BF, AE is a parallelogram: join AH, DF; and because AB is parallel to DC, and A BH to CF; the two straight lines AB, BH, which meet one another, are parallel to DC and CF which meet one another, and are not in the same plane D with the other two; wherefore they...
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A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 372 Seiten
...he proved that each of the figures CE, FG, GB, BF, AE is a parallelogram: Join AH, DF; and because AB is parallel to DC, and BH to CF ; the two straight...lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another, and are not in the same plane with the ether two ; wherefore they...
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - 1826 - 320 Seiten
...proved that eaeh of the figures CE, FG,GB, BF, AK is a parallelogram ; join AH, DF; and beeause \B is parallel to DC, and BH to CF; the two straight lines AB, BH, whieh meet one another, are parallel to DC and CF, whieh meet one another.; wherefore, though the first...
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The Elements of Euclid: The Errors by which Theon, Or Others, Have Long ...

Robert Simson - 1827 - 513 Seiten
...be proved that each of the figures CE, FG, GB, BF, AE, is a parallelogram. Join AH, DF; and because AB is parallel to DC, and BH to CF; the two straight...lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another, and are not in the 1 10. 11. •4. 1. • 34,. 1. SeeN. 1 36. 1....
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The Elements of Euclid: Viz, the First Six Books, Together with the Eleventh ...

Euclid, Robert Simson - 1829 - 516 Seiten
...be proved that each of the figures CE, FG, GB, BF, AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH to CF; the two straight lines AB, BII, which meet one another, are parallel to DC and CF which meet one another, and are not in the same...
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