Books 10-13 and appendixThe University Press, 1908 |
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Seite 42
Euclid. 15 the greater , and let there be applied to BC a parallel- ogram equal to the fourth part of the square on the less , A , that is , equal to the square on the half of A , and deficient 20 by a square figure . Let this be the ...
Euclid. 15 the greater , and let there be applied to BC a parallel- ogram equal to the fourth part of the square on the less , A , that is , equal to the square on the half of A , and deficient 20 by a square figure . Let this be the ...
Seite 126
... parallel to AB , and let the rest of the construction be as before ; it is then manifest that MO is the " side " of the area A GE F D M N B HK S R Q Р It is next to be proved that MO is the irrational line called major . Since AG is ...
... parallel to AB , and let the rest of the construction be as before ; it is then manifest that MO is the " side " of the area A GE F D M N B HK S R Q Р It is next to be proved that MO is the irrational line called major . Since AG is ...
Seite 191
... parallel to AČ . Now , since AF is commensurable in length wi therefore AG is also commensurable in length w the straight lines AF , FG . But AG is commensurable with AC ; therefore each of the straight lines AF , FG is com in length ...
... parallel to AČ . Now , since AF is commensurable in length wi therefore AG is also commensurable in length w the straight lines AF , FG . But AG is commensurable with AC ; therefore each of the straight lines AF , FG is com in length ...
Seite 212
... parallel to CD ; [ 11. 7 ] therefore each of the rectangles FO , LN is equal to the rectangle AG , GB . Now , since the squares on AG , GB are rational , and DM is equal to the squares on AG , GB , therefore DM is rational . And it has ...
... parallel to CD ; [ 11. 7 ] therefore each of the rectangles FO , LN is equal to the rectangle AG , GB . Now , since the squares on AG , GB are rational , and DM is equal to the squares on AG , GB , therefore DM is rational . And it has ...
Seite 216
... parallel to CD ; [ x . 73 ] therefore each of the rectangles FO , NL is equal to the rectangle AG , GB . Now , since the rectangle AG , GB is a mean proportional between the squares on AG , GB , and the square on AG is equal to CH , the ...
... parallel to CD ; [ x . 73 ] therefore each of the rectangles FO , NL is equal to the rectangle AG , GB . Now , since the rectangle AG , GB is a mean proportional between the squares on AG , GB , and the square on AG is equal to CH , the ...
Häufige Begriffe und Wortgruppen
area a medial base bimedial binomial straight line bisected circle ABCD commensurable in length commensurable in square cone cut in extreme cylinder decagon diameter dihedral angle dodecahedron equal equilateral Euclid extreme and mean greater segment height icosahedron inscribed irrational straight line kp² Lemma let the square magnitudes mean ratio medial area medial straight line medial whole parallel parallelepipedal solids parallelogram pentagon perpendicular plane of reference polygon prism Proclus PROPOSITION proved rational and incommensurable rational area rational straight line rectangle AC rectangle contained right angles second apotome side Similarly solid angle sphere square number square on AB squares on AC straight lines commensurable surable triangle twice the rectangle vertex whence
Beliebte Passagen
Seite 310 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 372 - Two unequal magnitudes being set out, if from the greater there be subtracted a magnitude greater than its half, and from that which is left a magnitude greater than its half, and if this process be repeated continually, there will be left some magnitude which will be less than the lesser magnitude set out?
Seite 260 - The inclination of a plane to a plane is the acute angle contained by two straight lines drawn from any the...
Seite 295 - BAE; and they are in one plane, which is impossible. Also, from a point above a plane, there can be but one perpendicular to that plane ; for, if there could be two, they would be parallel (6. PI.) to one another, which is absurd. Therefore, from the same point, &c.
Seite 279 - AB, CD. In like manner, it may be proved, that FE makes right angles with every straight line which meets it in that plane. But a straight line is at right angles to a plane when it makes right angles with every straight line which meets it in that plane : (xi. def. 3.) therefore EF is at right angles to the plane in which are AB, CD. Wherefore, if a straight line, &c.
Seite 389 - The upper end of the frustum of a pyramid or cone is called the upper base...
Seite 324 - AE is a parallelogram : join AH, DF ; and because AB is parallel to DC, and BH to CF ; the two straight lines AB, BH, which meet one another, are parallel to DC and CF, which meet one another...
Seite 294 - To erect a straight line at right angles to a given plane, from a point given in the plane. Let A be the point given in the plane.
Seite 304 - And because the plane AB is perpendicular to the third plane, and DE is drawn in the plane AB at right angles to AD their common section...
Seite 345 - N. equiangular to one another, each to each, that is, of which the folid angles are equal, each to each ; have to one another the ratio which is the fame with the ratio compounded of the ratios of their fides.