Library of Useful Knowledge: Geometry plane, solid, and spherical [by Pierce Morton] 1830. Elements of trigonometry, by W. Hopkins. 1833. Elements of spherical trigonometry, by A. De Morgan. A treatise on algebraical geometry, by S.W. Waud. 1835Baldwin & Craddock, 1835 |
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Seite 10
... drawn from the vertex A to the middle point of the base BC , is perpendicular to the base ( 6. Cor . 3. ) ; that is , a straight line AF may be drawn from the point A perpendicular to the straight line B C. But , from the same point A ...
... drawn from the vertex A to the middle point of the base BC , is perpendicular to the base ( 6. Cor . 3. ) ; that is , a straight line AF may be drawn from the point A perpendicular to the straight line B C. But , from the same point A ...
Seite 11
... drawn which is not at right angles to EF . Produce FE to G , so that EG may be equal to E F , and from G draw GH perpendicular to GF . Through E draw lm , making the angle G Em equal to the angle FEM . In FD take any point K : make G H ...
... drawn which is not at right angles to EF . Produce FE to G , so that EG may be equal to E F , and from G draw GH perpendicular to GF . Through E draw lm , making the angle G Em equal to the angle FEM . In FD take any point K : make G H ...
Seite 12
... draw HK perpendicular to CD ( 12. ) , and produce KH to meet A B in L. Then because the angle HEL is equal . to BE G ( 3. ) , and that B E G is equal to DFG or HFK , the angle HEL is equal to the angle H FK ( ax . 1. ) . The vertical ...
... draw HK perpendicular to CD ( 12. ) , and produce KH to meet A B in L. Then because the angle HEL is equal . to BE G ( 3. ) , and that B E G is equal to DFG or HFK , the angle HEL is equal to the angle H FK ( ax . 1. ) . The vertical ...
Seite 13
Bisect E F , and draw the straight line I. K , as before . Then , because LK is at right angles to C D , and that ... drawn through the same point to the same straight line . That which is given in the text , however , seems preferable ...
Bisect E F , and draw the straight line I. K , as before . Then , because LK is at right angles to C D , and that ... drawn through the same point to the same straight line . That which is given in the text , however , seems preferable ...
Seite 14
... Draw B M perpendicular to BA ( Post . 5. ) , and therefore ( 14. ) parallel to KH , and BN perpendicular to B C , and therefore parallel to K L. Then , by the first part of the proposition , the angle M BN is equal to HK L. But , be ...
... Draw B M perpendicular to BA ( Post . 5. ) , and therefore ( 14. ) parallel to KH , and BN perpendicular to B C , and therefore parallel to K L. Then , by the first part of the proposition , the angle M BN is equal to HK L. But , be ...
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A B C ABCD adjacent angles altitude apothem base BC bisect centre chord circum circumference circumscribed coincide common measure common section compounded cone conic section contained convex surface cylinder describe a circle diameter dihedral angle divided draw drawn edges equal angles equimultiples ference fore four magnitudes frustum given point given straight line gles harmonical harmonical mean Hence hyperbola hypotenuse inscribed join likewise locus meet parallel parallelogram parallelopiped pass pendicular pentagon perimeter perpendicular plane prism Prob produced PROP proposition pyramid quadrilateral radii radius rallel rectangle rectilineal figure regular polygon respectively right angles Scholium scribed segment sides A B similar solid angles sphere spherical angle square of A B straight lines A B tangent third three sides touch triangle ABC vertex vertical