Plane GeometrySilver, Burdett, 1896 - 253 Seiten |
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Seite 32
... many in the exterior angle at the third vertex ? 34. If the perpendicular from the vertex to the base of a triangle also bisects the base , the triangle is isosceles . PROPOSITION XIX 94. Theorem . If two angles of a 32 PLANE GEOMETRY.
... many in the exterior angle at the third vertex ? 34. If the perpendicular from the vertex to the base of a triangle also bisects the base , the triangle is isosceles . PROPOSITION XIX 94. Theorem . If two angles of a 32 PLANE GEOMETRY.
Seite 38
... bisects ABC . F Prove P = dist . from sides Draw PE and PFL to sides of Appl . Cons . Dem . rt . A = hyp . and acute ..PE = PF P dist . from sides [ = ] = QUADRILATERALS BP com . X = X ' - DEFINITIONS 102. A trapezium is a quadrilateral ...
... bisects ABC . F Prove P = dist . from sides Draw PE and PFL to sides of Appl . Cons . Dem . rt . A = hyp . and acute ..PE = PF P dist . from sides [ = ] = QUADRILATERALS BP com . X = X ' - DEFINITIONS 102. A trapezium is a quadrilateral ...
Seite 42
... bisect each other . A 3 B C 2 Appl . = Prove BO DO , and AO = CO Dem . 1 = 4 [ alt . int . ( s ) ] 2 = 3 [ alt . int . ( s ) ] ΔBC0 = Δ ADO [ s . and 2 adj . 4 ] .. BO DO = AO = CO PROPOSITION XXX 111. Theorem . The sum of the angles 42 ...
... bisect each other . A 3 B C 2 Appl . = Prove BO DO , and AO = CO Dem . 1 = 4 [ alt . int . ( s ) ] 2 = 3 [ alt . int . ( s ) ] ΔBC0 = Δ ADO [ s . and 2 adj . 4 ] .. BO DO = AO = CO PROPOSITION XXX 111. Theorem . The sum of the angles 42 ...
Seite 44
... bisects the third side , [ proved by noting its coincidence with a line drawn as in the theorem ( two lls to same line through one point , impossible ) ] . 115. Theorem . PROPOSITION XXXII The line joining the middle 44 PLANE GEOMETRY.
... bisects the third side , [ proved by noting its coincidence with a line drawn as in the theorem ( two lls to same line through one point , impossible ) ] . 115. Theorem . PROPOSITION XXXII The line joining the middle 44 PLANE GEOMETRY.
Seite 45
... AD [ CG = HD ( = ^ ) ] EF ( BC + AD ) = 116. Cor . A line drawn from the middle point of one leg of a trapezoid , parallel to the bases , bisects the other leg . PROPOSITION XXXIII 117. Theorem . The three bisectors of the MEDIANS 45.
... AD [ CG = HD ( = ^ ) ] EF ( BC + AD ) = 116. Cor . A line drawn from the middle point of one leg of a trapezoid , parallel to the bases , bisects the other leg . PROPOSITION XXXIII 117. Theorem . The three bisectors of the MEDIANS 45.
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Häufige Begriffe und Wortgruppen
AB² ABCD AC² acute angle AD² adjacent angles altitude angles are equal apothem Appl base and altitude base angle BC² BD² bisector bisects central angle centre chord circumf circumference circumscribed circle Cons decagon diagonals diameter dist distance divided Draw equal circles equally distant equiangular equiangular polygon equilateral triangle EXERCISES exterior angle feet figure Find its area Find the area geometric given circle given line given point homologous sides hypotenuse intersecting isosceles trapezoid isosceles triangle length locus logarithm mantissa mean proportional meas measure median middle point number of sides parallel parallelogram perimeter perpendicular Problem produced PROPOSITION quadrilateral radii radius ratio rectangle regular hexagon regular inscribed regular polygon respectively rhombus right angle right triangle secant segments similar triangles subtended tang tangent Theorem third side trapezoid triangle ABC triangles are equal vertex vertical angle
Beliebte Passagen
Seite 60 - A circle is a plane figure bounded by a curved line, called the circumference, every point of which is equally distant from a point within called the center.
Seite 219 - ... 4. Prove that, if from a point without a circle a secant and a tangent be drawn, the tangent is a mean proportional between the whole secant and the part without the circle.
Seite 139 - In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of these sides and the projection of the other side upon it.
Seite 44 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Seite 43 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 217 - Show that the areas of similar triangles are to each other as the squares of the homologous sides.
Seite 89 - Four quantities are in proportion when the ratio of the first to the second is equal to the ratio of the third to the fourth.
Seite 107 - If in a right triangle a perpendicular is drawn from the vertex of the right angle to the hypotenuse : I.
Seite 218 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. B' ADC A' D' C' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove = — • A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Seite 218 - Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides.