Elements of Geometry and Trigonometry: From the Works of A.M. LegendreA.S. Barnes, 1874 - 455 Seiten |
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Seite 93
... homologous . The corresponding angles are homologous angles , the corresponding sides are homologous sides , the corresponding diagonals are homologous diagonals , and so on . 3. SIMILAR ARCS , SECTORS , or SEGMENTS , in different ...
... homologous . The corresponding angles are homologous angles , the corresponding sides are homologous sides , the corresponding diagonals are homologous diagonals , and so on . 3. SIMILAR ARCS , SECTORS , or SEGMENTS , in different ...
Seite 118
... homologous angles are those included by sides respectively parallel or perpendicular to each other . Scholium . When two triangles have their sides perpen- licular , each to each , they may have a different relative position from that ...
... homologous angles are those included by sides respectively parallel or perpendicular to each other . Scholium . When two triangles have their sides perpen- licular , each to each , they may have a different relative position from that ...
Seite 120
... homologous sides are proportional ; hence , BD : AD :: AD : DC ; which was to be proved . Cor . 1. From the proportions , вс : AB :: AB : BD , and , ВС : АС :: AC : DC , we have ( B. II . , P. I. ) , and , AB2 = BC × BD , AC BC DC ...
... homologous sides are proportional ; hence , BD : AD :: AD : DC ; which was to be proved . Cor . 1. From the proportions , вс : AB :: AB : BD , and , ВС : АС :: AC : DC , we have ( B. II . , P. I. ) , and , AB2 = BC × BD , AC BC DC ...
Seite 122
... homologous , DE will be parallel to BC , and we shall have , AD : AB :: AE AC ; hence ( B. II . , P. IV . ) , we have , ADE : ABE :: ABE : ABC ; D that is , ABE is a mean proportional be- tween ADE and ABC . B PROPOSITION XXV . THEOREM ...
... homologous , DE will be parallel to BC , and we shall have , AD : AB :: AE AC ; hence ( B. II . , P. IV . ) , we have , ADE : ABE :: ABE : ABC ; D that is , ABE is a mean proportional be- tween ADE and ABC . B PROPOSITION XXV . THEOREM ...
Seite 123
... homologous sides . Let the triangles ABC and DEF be similar , the angle A being equal to the angle D , B to E , and C to F. then will the triangles be to each other as the squares of any two homologous sides . Because the angles A and D ...
... homologous sides . Let the triangles ABC and DEF be similar , the angle A being equal to the angle D , B to E , and C to F. then will the triangles be to each other as the squares of any two homologous sides . Because the angles A and D ...
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AB² ABCD AC² adjacent angles altitude apothem Applying logarithms base and altitude bisect centre chord circle circumference circumscribed coincide cone consequently convex surface corresponding cosec cosine Cotang cylinder denote diagonals diameter difference distance divided draw drawn edges equally distant feet find the area Formula frustum given angle given straight line greater hence homologous hypothenuse included angle interior angles intersection less Let ABC log sin lower base mantissa measured by half number of sides opposite parallel parallelogram parallelopipedon perimeter perpendicular plane MN polyedral angle polyedron prism PROPOSITION proved pyramid quadrant radii radius rectangle regular polygons right angles right-angled triangle Scholium secant segment semi-circumference side BC similar sine slant height sphere spherical polygon spherical triangle square subtracted Tang tangent THEOREM triangle ABC triangular prisms triedral angle upper base vertex vertices whence
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Seite 126 - The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302.
Seite 59 - A'B'C', and applying the law of cosines, we have cos a' = cos b' cos c' + sin b' sin c' cos A'. Remembering the relations a' = 180° -A, b' = 180° - B, etc. (this expression becomes cos A = — cos B cos C + sin B sin C cos a.
Seite 18 - The circumference of every circle is supposed to be divided into 360 equal parts called degrees, and each degree into 60 equal parts called minutes, and each minute into 60 equal parts called seconds, and these into thirds, fourths, &c.
Seite 104 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Seite 6 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Seite 28 - If two triangles have two sides of the one equal to two sides of the...
Seite 46 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 99 - The area of a parallelogram is equal to the product of its base and altitude.
Seite 172 - If two planes are perpendicular to 'each other, a straight line drawn in one of them, perpendicular to their intersection, will be perpendicular to the other.
Seite 214 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.