A Complete System of Mensuration of Superficies and Solids, of All Regular Figures: Calculated for the Use of Schools, Academies, and Private LearnersM'Elrath, Bangs & Company, 1833 - 159 Seiten |
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A Complete System of Mensuration of Superfices and Solids, of All Regular ... Tobias Ostrander Keine Leseprobe verfügbar - 2015 |
A Complete System of Mensuration of Superfices and Solids, of All Regular ... Tobias Ostrander Keine Leseprobe verfügbar - 2018 |
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12 feet 12 rods 18 inches 20 chains 20 inches 30 feet 9 inches abscissa acres angles bung diameter cask chains-What chord circle circumference conjugate diameters contained convex surface cube root cubic box cubic feet cubic inches cylinder diagonal dodecahedron equilateral triangle EXAMPLES feet 6 inches feet 9 feet-What find the area find the diameter find the length find the side find the solidity give the solidity given side head diameter hyperbola hypotenuse inches-What last product linear side middle diameter middle frustrum multiply the sum number of shot oblate spheroid ordinate parallel parallelopipedon pentagonal pyramid perches perpendicular altitude PROBLEM II PROBLEM VII prolate spheroid quotient rectangular parallelogram Required the length Required the solidity rhombus right-angled triangle rods-What roods Rule-To scalene triangle segment side required solid feet solidity required specific gravity square feet square rods square root square yards subtract thickness transverse and conjugate transverse diameter versed sine wine gallons
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Seite 74 - Take the length of the keel within board (so much as she treads on the ground) and the breadth within board by the midship beam, from plank to plank, and half the breadth for the depth, then multiply the length by the breadth, and that product by the depth, and divide the whole by 94; the quotient will give the true contents of the tonnage.
Seite 36 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Seite 51 - X 40) : 60 : 200 : 150 = the conjugate axis. 4. To find the transverse axis. Take the square root of the difference of the squares of the ordinate and half conjugate, and add to this the half conjugate if the lesser absciss is used, but subtract the half conjugate if the greater absciss is used.
Seite 124 - Square Measure 144 square inches = 1 square foot 9 square feet = 1 square yard...
Seite 121 - Add into one sum 39 times the square of the bung diameter, 25 times the square of the head diameter, and 26 times the product of the...
Seite 52 - Multiply the square root of half the sum of the squares of the two axes by *, and the product will be nearly = the circumference. Ex. Taking the same example as before, we hare /24' + IT \/ = — X 3,14159 = 66,6433= the circumference nearly.