 | William Nicholson - 1807 - 844 Seiten
...of the piston : 2d. When the length is given, divide the product found above, by the given length, and the square root of the quotient will be the diameter of the piston. In adjusting these dimensions, we have two circumstances of some importance to attend to; the... | |
 | William Templeton (engineer.) - 1833 - 224 Seiten
...multiply the required weight, in Ibs., by 1.62; divide the product by the diameter of the wheel in inches, and the square root of the quotient will be the diameter of the cross. section of the ring, in inches, nearly. Thus, .9ll6.» x 1.62 .„ ^"16x12 =8.7 Sometimes (for... | |
 | Alexander Jamieson - 1837 - 516 Seiten
...diameter of the forcing pump, and divide the product by the force with which the plunger descends ; then, the square root of the quotient will be the diameter of the cylinder sought. 127. EXAMPLE 4. The diameter of the cylinder is 5 inches, and the force with which the plunger... | |
 | Mechanics - 1837 - 350 Seiten
...fluid which maintains the equilibrium, and divide the product by the weight upon the bellows, then, the square root of the quotient will be the diameter of the equilibrating tube. * This equation for the diameter of the tube may be otherwise expressed ; thus... | |
 | Thomas Tredgold - 1842 - 350 Seiten
...times the weight in pounds ; when this product is divided by 500 times the length in feet, the cube root of the quotient will be the diameter of the cylinder in inches. The figure of equal strength is the same as in Case 1, art. 168. 172. Example. Required the diameter... | |
 | J. M. Scribner - 1849 - 286 Seiten
...Multiply the required weight in pounds by 1-62; divide the product by the diameter of the wheel in inches, and the square root of the quotient will be the diameter of the cross section of the ring in inches, nearly. Thus =7-7 inches. NOTE. The center of percussion in a... | |
 | William Templeton (engineer.) - 1852 - 284 Seiten
...RULE. — Multiply the number of gallons that the cylinder is required to contain by '2043, divide the product by the length in feet, and the square root of the quotient is the diameter in feet, and parts of a foot ; Or, multiply the number of gallons by -2043, and divide... | |
 | William Ezra Worthen - 1857 - 650 Seiten
...the pressure in tons. Or, the pressure in tons being given : Divide the given pressure in tons by 3, and the square root of the quotient will be the diameter of the piston in inches. Thus, the diameter of the piston being 10 inches, the thickness of metal 5 inches,... | |
 | W.E. WORTHEN - 1857 - 600 Seiten
...the pressure in tons. Or, the pressure in tons being given: Divide the given pressure in tons by 3, and the square root of the quotient will 'be the diameter of the piston in inches. Thus, the diameter of the piston being 10 inches, the thickness of metal 5 inches,... | |
 | James Foden - 1869 - 268 Seiten
...1. — Multiply the number of gallons that the cylinder is required to contain by -2043, divide the product by the length in feet, and the square root of the quotient win be the diameter in feet and parts of a foot. RULE 2. — Multiply the number of gallons by -2043,... | |
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... the square root of the quotient will be the diameter of the pump plunger in inches (allowing 5 per cent. 
