 | Robert Simson - 1762 - 466 Seiten
...bifected by the ftraight line AF. Which was to be done. . PROP. X. PROB. TO bifeft a given finite ftraight line, that is, to divide it into two equal parts. Let AB be the given ftraight line ; it is required to divide it into two equal parts. gf. Defcribe * upon it an equilateral... | |
 | Euclid - 1789 - 296 Seiten
...confequently the angle BAC is bifected by the right line AF, as was to be done. PRO p. X. PROBLEM. To bifect a given finite right line, that is, to divide it into two equal parts. Let AC be the given right line ; it is required to divide it into two equal parts. Upon AC defcribe the... | |
 | John Playfair - 1795 - 444 Seiten
...the ftraight line AF. Which was to be done. b II c8.u PRO PX PRO B. 3 bifedl a given finite ftraight line, that is, to divide it into two equal parts. Let AB be the given ftraight line ; it is required to divide it into two equal parts. Defcribe a upon it an equilateral... | |
 | Alexander Ingram - 1799 - 351 Seiten
...by the ftraight line AF. Wrhich was to be done. I PROP. X. PROB. TO bifect a given finite ftraight line, that is, to divide it into two equal parts. Let AB be the given ftraighi line ; it is required to divide it into two equal parts. Defcribe a upon it an equilateral... | |
 | John Bonnycastle - 1803 - 470 Seiten
...confequentty *be awgle B AC IB btfected by the rigkt line AF, as was to be done. PROP. X. PROBLEM. To bife6t a given finite right line, that is, to divide it into two equal parts. V Let AC be the given right fine ; it is required to divide it into two equal parts. Upon AC defcribe... | |
 | John Playfair - 1804 - 470 Seiten
...two fides EA, AF, each to each ; but the bafe DF is alfo equal to the bafe EF ; therefore the angle DAF is equal £ to the angle EAF ; wherefore the given rectilineal angle BAC is bifefted by the ftraight line AF. Which was to be done. PROP. X. PROB. TO bifed a given finite ftraight... | |
 | Euclides - 1814 - 558 Seiten
...EA, AF, each to each; and the base DF is equal to the basej EF; therefore the angle DAF is equal 0 to the angle EAF ; wherefore the given rectilineal angle BAC is bisected by the straight line AF. Which was to be done. an equilateral triangle DEF; then join AF; the straight line... | |
 | Euclides - 1816 - 528 Seiten
...straight line AF. " . Which was tobe ilone. ; , . • PROP. X. .PROB. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line ;, it is required to divide it into two equal parts. Describe11 upon it an equilateral... | |
 | Euclid, John Playfair - 1819 - 348 Seiten
...bisected by the straight line AF. Which w?s to be done,. PROP. X. PROB. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line ; it is required to divide it into two equal parts. Describe (1. 1.) upon it an equilateral... | |
 | John Playfair - 1819 - 317 Seiten
...each to each ; but the base DF is also equal to the base EF ; therefore the angle DAF is equal (8. 1.) to the angle EAF : wherefore the given rectilineal angle BAC is bisected by the straight line AF. Which was to be done. PROP. X. PROB. To bisect a given finite straight line, that... | |
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To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts. 
