The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method ...H. Woodfall, 1740 - 283 Seiten |
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Seite 42
... Solution . Set the firft on B , to the fecond on A , then oppofite the third on B , is the fourth on A. For let us denote the three Numbers by a , b , c ,. and that fought by x , then a : b ::: ; therefore bxc ( per 16. VIth Euclid ) x ...
... Solution . Set the firft on B , to the fecond on A , then oppofite the third on B , is the fourth on A. For let us denote the three Numbers by a , b , c ,. and that fought by x , then a : b ::: ; therefore bxc ( per 16. VIth Euclid ) x ...
Seite 45
Robert Shirtcliffe. Solution . Set the firft Root on D to the third Term on C , then on C oppofité the second Root on D , is the Term required . For let the three Terms given be denoted by a , b , c , and x the Term fought , then a2 : b2 ...
Robert Shirtcliffe. Solution . Set the firft Root on D to the third Term on C , then on C oppofité the second Root on D , is the Term required . For let the three Terms given be denoted by a , b , c , and x the Term fought , then a2 : b2 ...
Seite 49
... Solution . Set the first on D to the third on E , then oppofite to the fecond on D is the fourth on E. For let us again denote the three given Num- bers by a , b , c , and x for that fought , then by the Condition of the Queftion a3b3 ...
... Solution . Set the first on D to the third on E , then oppofite to the fecond on D is the fourth on E. For let us again denote the three given Num- bers by a , b , c , and x for that fought , then by the Condition of the Queftion a3b3 ...
Seite 51
... Solution . Set the Length on B to the Breadth on MD , then oppofite 1 ( or unity ) on MD is the Measure on B. For the Measure of the Breadth being b , and that of its Length 1 , the Measure of the Rectangle iş bxl , as is demonftrated ...
... Solution . Set the Length on B to the Breadth on MD , then oppofite 1 ( or unity ) on MD is the Measure on B. For the Measure of the Breadth being b , and that of its Length 1 , the Measure of the Rectangle iş bxl , as is demonftrated ...
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The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method ... Robert Shirtcliffe Keine Leseprobe verfügbar - 2018 |
The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method Robert Shirtcliffe Keine Leseprobe verfügbar - 2018 |
The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method Robert Shirtcliffe Keine Leseprobe verfügbar - 2023 |
Häufige Begriffe und Wortgruppen
Abfciffa againſt Ale Gall alfo alſo Angle Area Bafe Baſe becauſe betwixt Breadth Bung-Diameter Cafk called Caſk Chap Circle circular Segment Cone Conic Conic Sections Conoid Content Corol correfponding Curve Decimal denote Diam Diſtance divided Divifion Divifor dry Inches Ellipfe equal Example expreffed faid fame fecond fhall fhew fhewn Figure fimilar fince firft firſt fome Fruftum ftand fuch fufficient fuppofe fure Gauging given gives Height hence Hoof Hyperbola Hyperbolic Segment laft laſt Lemma Length Logarithms mean Diameter Meaſure Method multiplied muſt Number oppofite Ordinate orems parabolic parallel perpendicular Plane Points Product Prop Propofition Quotient Radius Reaſon refpectively Root Rule Scholium Section Segment ſhall Side Sliding-Rule Solid Spheroid Spindle Square taken Terms thefe Theorem thereof theſe thofe thoſe thro tranfverfe Axis Triangle Ullage uſe verfed Sine Vertex wet Inches whence whofe Wine Gallons
Beliebte Passagen
Seite 59 - The circumference of every circle is supposed to be divided into 360 equal parts called degrees, and each degree into 60 equal parts called minutes, and each minute into 60 equal parts called seconds, and these into thirds, fourths, &c.
Seite 7 - In multiplication of decimals, we know that the number of decimal places in the product is equal to the sum of those in both the factors.
Seite 97 - J of the square of their difference, then multiply by the hight, and divide as in the last rule. Having the diameter of a circle given, to find the area. RULE. — Multiply half the diameter by half the circumference, and the product is the area ; or, which is the same thing, multiply the square of the diameter by .7854, and the product is the area.
Seite 282 - Sort is, to multiply the two Weights together, and extract the Square Root of. the Product, which Root will be the true Weight.
Seite 283 - Backs time ufed, and become more and more uneven as they grow older, efpecially fuch as are not every where well and equally fupported ; many of them...
Seite 187 - Sum of thofe next to them, C the Sum of the two next following the laft, and fo on ; then we (hall have the following fables of Areas, for the feveral Numbers of Ordinates prefixt againft them, viz.
Seite 86 - Progreflion from o, is equal to the Product of the laft Term by the Number of Terms, and this divided by the Index (m) plus Unity.
Seite 272 - To half the Sum of the Squares of the Top and Bottom Diams.
Seite 95 - The latter being taken from the former, leaves 3.14.15.9265.5 for the Length of half the Circumference of a Circle whofe Radius is Unity : Therefore the Diameter of any Circle is to its Circutuftrence as I is to 3.1415.9265.5 nearly.
Seite 86 - Numbr infinitely greAt, therefore the firft Term of the above Value of /, muft be infinitely greater than any of the...