Plane Geometry: With Problems and ApplicationsAllyn and Bacon, 1910 - 280 Seiten |
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Ergebnisse 1-5 von 46
Seite 55
... ABCD , a parallelogram ; that is , AB || CD and AD || BC . To prove that AB = CD and BC = AD . Proof : Draw the diagonal AC . Prove △ ABC A ACD and compare corresponding sides . What determines which are corresponding sides ? 140 ...
... ABCD , a parallelogram ; that is , AB || CD and AD || BC . To prove that AB = CD and BC = AD . Proof : Draw the diagonal AC . Prove △ ABC A ACD and compare corresponding sides . What determines which are corresponding sides ? 140 ...
Seite 56
... ABCD with its diagonals meeting at the point 0 . To prove that OC = OA and OB = OD . Proof : In the triangles AOB and COD , determine whether sufficient parts are equal to make them congruent , and if so compare corresponding parts ...
... ABCD with its diagonals meeting at the point 0 . To prove that OC = OA and OB = OD . Proof : In the triangles AOB and COD , determine whether sufficient parts are equal to make them congruent , and if so compare corresponding parts ...
Seite 57
... ABCD is a parallelogram . ) Proof : From the data given prove that AABC = A BDC . Use corresponding angles of these congruent triangles to show that the other two opposite sides are parallel . Hence show that the figure is a ...
... ABCD is a parallelogram . ) Proof : From the data given prove that AABC = A BDC . Use corresponding angles of these congruent triangles to show that the other two opposite sides are parallel . Hence show that the figure is a ...
Seite 58
... ABCD with AC = BD . To prove that 21 22 23 24 = rt . 4 . = = = Proof : Show that △ ABD≈ △ ABC . .. ≤1 = ≤ 3 . ( Why ? ) But 21+ Z3 = 2 rt . 4 . ( Why ? ) .. 2123 = rt . 4 . ( Why ? ) In like manner prove that ≤ 2 = 24 = rt . 2 ...
... ABCD with AC = BD . To prove that 21 22 23 24 = rt . 4 . = = = Proof : Show that △ ABD≈ △ ABC . .. ≤1 = ≤ 3 . ( Why ? ) But 21+ Z3 = 2 rt . 4 . ( Why ? ) .. 2123 = rt . 4 . ( Why ? ) In like manner prove that ≤ 2 = 24 = rt . 2 ...
Seite 59
... ABCD and A'B'C'D ' such that AB = A'B ' , AD = A'D ' and A = A ' . To prove that ☐ ABCD A'B'C'D ' . Proof : Apply ABCD to A'B'C'D ' so as to make A coincide with △ A ' , AB falling on A'B ' , and AD on A'D ' . Then BC takes the ...
... ABCD and A'B'C'D ' such that AB = A'B ' , AD = A'D ' and A = A ' . To prove that ☐ ABCD A'B'C'D ' . Proof : Apply ABCD to A'B'C'D ' so as to make A coincide with △ A ' , AB falling on A'B ' , and AD on A'D ' . Then BC takes the ...
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Häufige Begriffe und Wortgruppen
ABCD accompanying design altitude apothem arcs area bounded axes of symmetry axioms base and altitude bisectors bisects central angle chord circumference congruent corresponding sides definite diagonal diameter divided Draw drawn equal angles equal circles equilateral triangle EXERCISES exterior angle feet Find the area Find the locus Find the radius fixed point geometric Give the proof given circle given point given triangle greater Hence hypotenuse inscribed intersect isosceles triangle length line-segment measure meet middle points number of sides Outline of Proof parallel lines parallelogram perimeter perpendicular proof in full Prove quadrilateral radii ratio rectangle regular dodecagon regular hexagon regular octagon regular polygon regular triangle respectively rhombus right angle right triangle secant semicircle Show shown straight angle straight line strip subtend SUGGESTION tangent THEOREM tile trapezoid triangle ABC unit vertex vertices width
Beliebte Passagen
Seite 215 - If two triangles have two sides of the one equal to two sides of the other...
Seite 35 - An exterior angle of a triangle is equal to the sum of the two opposite interior angles.
Seite 22 - Any side of a triangle is less than the sum of the other two sides...
Seite 113 - Sines that the bisector of an angle of a triangle divides the opposite side into parts proportional to the adjacent sides.
Seite 273 - This textbook may be borrowed for two weeks, with the privilege of renewing it once. A fine of five cents a day is incurred by failure to return a book on the date when it is due. The Education Library is open from 9 to 5 daily except Saturday when it closes at 12.30.
Seite 52 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Seite 174 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Seite 153 - The formula states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the base and altitude.
Seite 219 - Find the locus of a point such that the difference of the squares of its distances from two fixed points is a constant.
Seite 202 - The area of a rectangle is equal to the product of its base and altitude.