Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with Appendix by Thos. Kirkland. the first six booksA. Miller & Company, 1876 - 403 Seiten |
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Seite 3
... semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter . XIX . The center of a semicircle is the same with that of the circle . XX . Rectilineal figures are those which are contained ...
... semicircle is the figure contained by a diameter and the part of the circumference cut off by the diameter . XIX . The center of a semicircle is the same with that of the circle . XX . Rectilineal figures are those which are contained ...
Seite 44
... semicircle ; or without the figure , as in certain conic fines . ' Def . XXIV - XXIX . Triangles are divided into three classes , by reference to the relations of their sides ; and into three other classes , by reference to their angles ...
... semicircle ; or without the figure , as in certain conic fines . ' Def . XXIV - XXIX . Triangles are divided into three classes , by reference to the relations of their sides ; and into three other classes , by reference to their angles ...
Seite 98
... semicircle BHF , and produce DE to meet the circumference in H. The square described upon EH shall be equal to the given recti lineal figure 4 . 2 Join GH . Then because the straight line BF is divided into two equal parts in the point ...
... semicircle BHF , and produce DE to meet the circumference in H. The square described upon EH shall be equal to the given recti lineal figure 4 . 2 Join GH . Then because the straight line BF is divided into two equal parts in the point ...
Seite 113
... semicircle ADB . At the point B draw BE at right angles to AB and equal to M. Through E , draw ED parallel to AB and cutting the semicircle in D ; and draw DF parallel to EB meeting AB in F. Then AB is divided in F , so that the ...
... semicircle ADB . At the point B draw BE at right angles to AB and equal to M. Through E , draw ED parallel to AB and cutting the semicircle in D ; and draw DF parallel to EB meeting AB in F. Then AB is divided in F , so that the ...
Seite 138
... semicircle . B AE D C Draw AF to the center , and produce it to C , and join CE . Because AC is a diameter of the circle , { therefore the segment BADC is greater than a semicircle and the angles in it BAC , BEC are equal , hy the first ...
... semicircle . B AE D C Draw AF to the center , and produce it to C , and join CE . Because AC is a diameter of the circle , { therefore the segment BADC is greater than a semicircle and the angles in it BAC , BEC are equal , hy the first ...
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Häufige Begriffe und Wortgruppen
A₁ ABCD AC is equal Algebraically angle ABC angle ACB angle BAC angle equal Apply Euc base BC chord circle ABC constr describe a circle diagonals diameter divided draw equal angles equiangular equilateral triangle equimultiples Euclid exterior angle Geometrical given circle given line given point given straight line gnomon greater hypotenuse inscribed intersection isosceles triangle less Let ABC line BC lines be drawn multiple opposite angles parallelogram parallelopiped pentagon perpendicular plane polygon produced Prop proportionals proved Q.E.D. PROPOSITION quadrilateral quadrilateral figure radius ratio rectangle contained rectilineal figure remaining angle right angles right-angled triangle segment semicircle shew shewn similar similar triangles solid angle square on AC tangent THEOREM touch the circle triangle ABC twice the rectangle vertex vertical angle wherefore
Beliebte Passagen
Seite 93 - If a straight line be bisected and produced to any point, the square on the whole line thus produced, and the square on the part of it produced, are together double of the square on half the line bisected, and of the square on the line made up of the half and the part produced. Let the straight line AB be bisected in C, and produced to D ; The squares on AD and DB shall be together double of the squares on AC and CD. CONSTRUCTION. — From the point C draw CE at right angles to AB, and make it equal...
Seite 118 - Guido, with a burnt stick in his hand, demonstrating on the smooth paving-stones of the path, that the square on the hypotenuse of a right-angled triangle is equal to the sum of the squares on the other two sides.
Seite 145 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle ; the angles which this line makes with the line touching the circle, shall be equal to the angles which are in the alternate segments of the circle.
Seite 88 - If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Seite 26 - ... upon the same side together equal to two right angles, the two straight lines shall be parallel to one another.
Seite 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Seite 144 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Seite 92 - If a straight line be divided into two equal, and also into two unequal parts, the squares on the two unequal parts are together double of the square on half the line and of the square on the line between the points of section. Let the straight line AB be divided into two equal parts...
Seite xv - In every triangle, the square of the side subtending either of the acute angles is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle.
Seite 67 - A proposition affirming the possibility of finding such conditions as will render a certain problem indeterminate or capable of innumerable solutions.