Euclid's Elements of Geometry,: From the Latin Translation of Commandine. To which is Added, A Treatise of the Nature of Arithmetic of Logarithms; Likewise Another of the Elements of Plain and Spherical Trigonometry; with a Preface...Tho. Woodward at the Half-Moon, between the Two Temple-Gates in Fleet-street; and sold by, 1733 - 397 Seiten |
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Seite 276
... Radius . For ( by 15. El . 4. ) the Side of an Hexagon inferib'd in a Circle , that is , the Subtenfe of 60 Degrees is equal to the Radius . A Sine divides the Radius into two Segments CE , EB ; one of which , CE , which is in ...
... Radius . For ( by 15. El . 4. ) the Side of an Hexagon inferib'd in a Circle , that is , the Subtenfe of 60 Degrees is equal to the Radius . A Sine divides the Radius into two Segments CE , EB ; one of which , CE , which is in ...
Seite 277
... Radius CP , being given , to find the Cofine DF . TH 1 HE Radius CD and the Sine DE , being given in the Right - angled Triangle CDE , there will be given ( by the laft Prop . ) ✓CDq - DEq = DF . T 2 PRO- PROPOSITION INI . PROBLEM ...
... Radius CP , being given , to find the Cofine DF . TH 1 HE Radius CD and the Sine DE , being given in the Right - angled Triangle CDE , there will be given ( by the laft Prop . ) ✓CDq - DEq = DF . T 2 PRO- PROPOSITION INI . PROBLEM ...
Seite 278
... Radius . Therefore DE , EB , being given in the Right - angled Triangle DBE , there will be given DB , whofe half DM is the Sine of the Arc DL the Arc BD . PROPOSITION IV . PROBLEM . The Sine BM of the Arc BL being given , to find the ...
... Radius . Therefore DE , EB , being given in the Right - angled Triangle DBE , there will be given DB , whofe half DM is the Sine of the Arc DL the Arc BD . PROPOSITION IV . PROBLEM . The Sine BM of the Arc BL being given , to find the ...
Seite 279
... Radius CD be drawn , and then CO is the Cofine of the Arc FD , which accordingly is given , and draw OP thro ' O parallel to DK . Alfo let OM , GE , be drawn parallel to CB . Then be- cause the Triangles CDK , COP , CHI , FOH , FOM ...
... Radius CD be drawn , and then CO is the Cofine of the Arc FD , which accordingly is given , and draw OP thro ' O parallel to DK . Alfo let OM , GE , be drawn parallel to CB . Then be- cause the Triangles CDK , COP , CHI , FOH , FOM ...
Seite 280
... Radius is to double the Co- fine of 15 Degrees , as the Sine of 1 Degree , is to the Difference of the Sines of 14 Degrees , and 16 Degrees ; fo alfo is the Sine of 3 Degrees , to the Difference between the Sines of 12 and 18 Degrees ...
... Radius is to double the Co- fine of 15 Degrees , as the Sine of 1 Degree , is to the Difference of the Sines of 14 Degrees , and 16 Degrees ; fo alfo is the Sine of 3 Degrees , to the Difference between the Sines of 12 and 18 Degrees ...
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Euclid's Elements of Geometry: From the Latin Translation of Commandine. to ... John Keill Keine Leseprobe verfügbar - 2014 |
Häufige Begriffe und Wortgruppen
adjacent Angles alfo equal alſo Angle ABC Angle BAC Bafe Baſe becauſe bifected Center Circle ABCD Circumference Cofine Cone confequently Coroll Cylinder defcribed demonftrated Diameter Diſtance drawn thro EFGH equal Angles equiangular Equimultiples faid fame Altitude fame Multiple fame Plane fame Proportion fame Reaſon fecond fhall be equal fimilar fince firft firſt folid Parallelepipedon fome fore ftand fubtending given Right Line Gnomon greater join leffer lefs leſs likewife Logarithm Magnitudes Meaſure Number Parallelogram perpendicular Polygon Priſms Prop PROPOSITION Pyramid Pyramid ABCG Quadrant Ratio Rectangle Rectangle contained remaining Angle Right Angles Right Line AC Right-lined Figure Segment ſhall Sine Solid Sphere Subtangent themſelves THEOREM theſe thofe thoſe Triangle ABC Unity Vertex the Point Wherefore whofe Bafe whole whoſe Baſe
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Seite 66 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Seite 163 - IF two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals : the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Seite 112 - And in like manner it may be shown that each of the angles KHG, HGM, GML is equal to the angle HKL or KLM ; therefore the five angles GHK, HKL, KLM, LMG, MGH...
Seite 90 - IN a circle, the angle in a semicircle is a right angle ; but the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Seite 22 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB...
Seite 10 - ... equal to them, of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but the base CB greater than the base EF ; the angle BAC is likewise greater than the angle EDF.
Seite 15 - CF, and the triangle AEB to the triangle CEF, and the remaining angles to the remaining angles, each to each, to which...
Seite 33 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other, (i.
Seite 113 - If two right-angled triangles have their hypotenuses equal, and one side of the one equal to one side of the other, the triangles are congruent.