The school Euclid: comprising the first four books, by A.K. Isbister1862 |
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Seite 42
... parallelogram is a four - sided figure , of which the opposite sides are parallel ; and the diameter is the straight line joining two of its opposite angles . ( References - Prop . I. 4 , 26 , 29 ; ax . 2. ) Let ACDB be a parallelogram ...
... parallelogram is a four - sided figure , of which the opposite sides are parallel ; and the diameter is the straight line joining two of its opposite angles . ( References - Prop . I. 4 , 26 , 29 ; ax . 2. ) Let ACDB be a parallelogram ...
Seite 43
... parallelogram are equal to one another . Also the diameter shall bisect it . For because AB is equal to CD ; and BC common , the two AB , BC , are equal to the two DC , CB , each to each ; and the angle ABC has been proved equal to the ...
... parallelogram are equal to one another . Also the diameter shall bisect it . For because AB is equal to CD ; and BC common , the two AB , BC , are equal to the two DC , CB , each to each ; and the angle ABC has been proved equal to the ...
Seite 44
... parallelogram ABCD shall be equal to the parallelogram EBCF . A D F B DEMONSTRATION If the sides AD , DF , of the parallelograms ABCD , DBCF , opposite to the base BC , be terminated in the same point D , it is plain that each of the ...
... parallelogram ABCD shall be equal to the parallelogram EBCF . A D F B DEMONSTRATION If the sides AD , DF , of the parallelograms ABCD , DBCF , opposite to the base BC , be terminated in the same point D , it is plain that each of the ...
Seite 45
... parallelogram ABCD shall be equal to the parallelogram EFGH . A DE H B C F G CONSTRUCTION From B to E , draw the straight line BE , and from C to H , the straight line CH . DEMONSTRATION Because BC is equal to FG , ( hyp . ) and FG to ...
... parallelogram ABCD shall be equal to the parallelogram EFGH . A DE H B C F G CONSTRUCTION From B to E , draw the straight line BE , and from C to H , the straight line CH . DEMONSTRATION Because BC is equal to FG , ( hyp . ) and FG to ...
Seite 46
... parallelogram ABCD is equal to the parallelogram EBCH ; ( 1.35 ) for the like reason , the parallelogram EFGH is equal to the same EBCH ; therefore the parallelogram ABCD is equal to the paral- lelogram EFGH . ( ax . 1. ) Wherefore ...
... parallelogram ABCD is equal to the parallelogram EBCH ; ( 1.35 ) for the like reason , the parallelogram EFGH is equal to the same EBCH ; therefore the parallelogram ABCD is equal to the paral- lelogram EFGH . ( ax . 1. ) Wherefore ...
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The School Euclid: Comprising the First Four Books, Chiefly from the Text of ... A. K. Isbister Keine Leseprobe verfügbar - 2009 |
Häufige Begriffe und Wortgruppen
AB is equal adjacent angles alternate angles angle ABC angle AGH angle BAC angle BCD angle EAB angle EDF angle equal angles CBA base BC BC is equal circle ABC constr DEMONSTRATION describe the circle diameter double equal angles equal straight lines equal to BC equilateral and equiangular exterior angle given circle given rectilineal angle given straight line gnomon greater inscribed interior and opposite less Let ABC Let the straight opposite angles parallel to CD parallelogram pentagon perpendicular Q. E. D. PROP rectangle AE rectangle contained rectilineal figure References Prop References-Prop remaining angle required to describe right angles segment semicircle side BC square of AC straight line AB straight line AC THEOREM touches the circle triangle ABC triangle DEF twice the rectangle
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Seite 141 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Seite 35 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Seite 71 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square of the side subtending the obtuse angle, is greater than the squares of the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle, between the perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle...
Seite 33 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Seite 61 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square of...
Seite 43 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Seite 27 - ... shall be greater than the base of the other. Let ABC, DEF be two triangles, which have the two sides AB, AC, equal to the two DE, DF, each to each, viz.
Seite 77 - An angle in a segment is the angle contained by two straight lines drawn from any point in the circumference of the segment to the extremities of the straight line which is the base of the segment.
Seite 15 - The angles which one straight line makes with another upon one side of it, are either two right angles, or are together equal to two right angles.