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Seite 6 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator: then reduce the new fraction to its lowest terms.
Seite 30 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Seite 222 - As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base.
Seite 145 - FRUSTUM, in mathematics ; a part of some solid body separated from the rest. The frustum of a cone is the part that remains, when the top is cut oft by a plane parallel to the base, and is otherwise called a truncated cone.
Seite 359 - ... years, amounts to a whole day. By which the Vernal Equinox was anticipated ten days, from the time of the general council of Nice, held in...
Seite 228 - When you have proved that the three angles of every triangle are equal to two right angles...
Seite 359 - October, in 1582, to make the equinox fall on the twenty-first of March, as it did at the time of that council ; and to prevent the like variation for the future, he ordered that three days should be abated in every four hundred years by reducing the leap year at the close of each century for three successive centuries to common years, and retaining the leap year at the close of each fourth century only. This was at that time esteemed...
Seite 145 - Multiply the diameters of the two bases together, and to the product add one third of the square of the difference of the diameters : then multiplying this sum by 7854...
Seite 132 - Dimensions of any of the parts nf a Circle being given, to find the side of a square equal to the Circle. RULE. If the area of the circle be given, extract the square root of the area, which will be the side of a square equal to the circle : If the diameter or circumference be given, find the area by Art.
Seite 130 - To find the area of a Circle. ' RULE. Multiply half the diameter by half the circumference, and the product is the area...