Euclid's Elements of geometry, books i. ii. iii. iv1862 |
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Seite 22
... reason , CEB , the exterior angle of the tri- angle ABE , is greater than the angle BAE . 3. And it has been shown that the angle BDC is greater than CEB . 4. Much more then is the angle BDC greater than the angle BAC . Conclusion ...
... reason , CEB , the exterior angle of the tri- angle ABE , is greater than the angle BAE . 3. And it has been shown that the angle BDC is greater than CEB . 4. Much more then is the angle BDC greater than the angle BAC . Conclusion ...
Seite 36
... reason , the parallelogram EFGH is equal to the same EBCH . 8. Therefore the parallelogram ABCD is equal to the paral- lelogram EFGH . ( ax . 1. ) Conclusion . Therefore , parallelograms , & c . Q. E. D. PROPOSITION 37. - THEOREM ...
... reason , the parallelogram EFGH is equal to the same EBCH . 8. Therefore the parallelogram ABCD is equal to the paral- lelogram EFGH . ( ax . 1. ) Conclusion . Therefore , parallelograms , & c . Q. E. D. PROPOSITION 37. - THEOREM ...
Seite 41
... reason the tri- angle KGC is equal to the triangle KFC . 4. Therefore , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to KFC ; B E A H K 5. The triangles AEK , KGC , are equal to the triangles AHK , KFC ...
... reason the tri- angle KGC is equal to the triangle KFC . 4. Therefore , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to KFC ; B E A H K 5. The triangles AEK , KGC , are equal to the triangles AHK , KFC ...
Seite 45
... , upon opposite sides of AB , make with it at the point A , the adjacent angles equal to two right angles ; 3. Therefore CA is in the same straight line with AG . - ( I . 14. ) 4. For the same reason , AB and AH are BOOK I. PROP . 47 . 45.
... , upon opposite sides of AB , make with it at the point A , the adjacent angles equal to two right angles ; 3. Therefore CA is in the same straight line with AG . - ( I . 14. ) 4. For the same reason , AB and AH are BOOK I. PROP . 47 . 45.
Seite 46
Euclides. 4. For the same reason , AB and AH are in the same straight line . 5. Now the angle DBC is equal to the angle FBA , for each of them is a right angle ( ax . 11 ) , add to each the angle ABC . 6. Therefore the whole angle DBA is ...
Euclides. 4. For the same reason , AB and AH are in the same straight line . 5. Now the angle DBC is equal to the angle FBA , for each of them is a right angle ( ax . 11 ) , add to each the angle ABC . 6. Therefore the whole angle DBA is ...
Häufige Begriffe und Wortgruppen
AB is equal AC and CB adjacent angles angle ABC angle AGH angle BAC angle BCD angle EAB angle EDF angle equal angles CBA base BC BC is equal bisected circle ABC circumference Conclusion Conclusion.-Therefore const Construction.-1 Demonstration.-1 describe the circle diameter double equal angles equal to CD equiangular exterior angle given circle given point given rectilineal angle given straight line Given.-Let ABCD gnomon greater Hypothesis inscribed interior and opposite isosceles triangle less opposite angle parallel to CD parallelogram perpendicular point F produced Q. E. D. PROPOSITION rectangle AB BC rectangle AE rectangle contained rectilineal figure References-Prop remaining angle required to describe right angles segment semicircle Sequence side BC square on AC straight line AC straight line drawn touches the circle triangle ABC triangle DEF twice the rectangle
Beliebte Passagen
Seite 25 - If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz.
Seite 2 - A circle is a plane figure contained by one line, which is called the circumference, and is such that all straight lines drawn from a certain point within the figure to the circumference, are equal to one another.
Seite 99 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Seite 4 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Seite 66 - ... the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse...
Seite 65 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.
Seite 32 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 58 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced...
Seite 88 - The straight line drawn at right angles to the diameter of a circle, from the extremity of it, falls without the circle...
Seite 33 - The straight lines which join the extremities of two equal and parallel straight lines towards the same parts, are also themselves equal and parallel.