A Treatise on Special Or Elementary Geometry: Including an Elementary, and Also, in Part III, a Higher Course, in Plane, Solid, and Spherical Geometry; and Plane and Spherical Trigonometry, with the Necessary TablesSheldon, 1879 - 440 Seiten |
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Seite 2
... solution tells how a thing is done : a demon- stration tells why it is so done . A demonstration is often called proof . 6. A Lemma is a theorem demonstrated for the purpose of using it in the demonstration of another theorem . ILL ...
... solution tells how a thing is done : a demon- stration tells why it is so done . A demonstration is often called proof . 6. A Lemma is a theorem demonstrated for the purpose of using it in the demonstration of another theorem . ILL ...
Seite 3
... Solution is the process of performing a problem or an example . It should usually be accompanied by a demonstration ... solution and a demonstration . Rule . Solution . Scholium . I. SECTION II . THE GEOMETRICAL CONCEPTS . * POINTS . 13 ...
... Solution is the process of performing a problem or an example . It should usually be accompanied by a demonstration ... solution and a demonstration . Rule . Solution . Scholium . I. SECTION II . THE GEOMETRICAL CONCEPTS . * POINTS . 13 ...
Seite 12
... SOLUTION . - Let AB , Fig . 15 , be the line to be measured . Take the dividers , E F G H FIG . 15 . Fig . 1 ( frontispiece ) , and placing the sharp point A firmly upon the end A of the line AB , open the dividers till the other point ...
... SOLUTION . - Let AB , Fig . 15 , be the line to be measured . Take the dividers , E F G H FIG . 15 . Fig . 1 ( frontispiece ) , and placing the sharp point A firmly upon the end A of the line AB , open the dividers till the other point ...
Seite 13
... SOLUTION . - To find the sum of AB and CD , I * first draw the indefinite line Ex . With the dividers I obtain the length of AB , by placing one point on A and extending the other to B. This length I now lay off on the indefinite line ...
... SOLUTION . - To find the sum of AB and CD , I * first draw the indefinite line Ex . With the dividers I obtain the length of AB , by placing one point on A and extending the other to B. This length I now lay off on the indefinite line ...
Seite 15
... SOLUTION . - To bisect the line AB , I take the dividers ; and opening them so that the line between their points is more than half as long as AB , I place the sharp point A on the point A , and holding it firmly there , make a little ...
... SOLUTION . - To bisect the line AB , I take the dividers ; and opening them so that the line between their points is more than half as long as AB , I place the sharp point A on the point A , and holding it firmly there , make a little ...
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Häufige Begriffe und Wortgruppen
ABCD adjacent altitude angle or arc bisect centre chord circle circumference coincide common point conceive construct cosec cosine cotangent DEM.-Let diagonals diameter dicular diedral distance divided draw drawn edge equal angles equiangular equilateral equivalent exterior angle facial angles figure frustum Geometry given line given point greater Hence hypotenuse included angle inscribed intersect isosceles less let fall locus logarithms lune measured middle point opposite sides parallel parallelogram parallelopiped passing pendicular perpen perpendicular plane triangle prism Prob Prob.-To project the triangle PROP PROPOSITION pyramid quadrant quadrilateral radii radius rectangle regular polygon revolve right angled triangle secant secant line similar similar triangles sine solid solution sphere spherical angle spherical triangle square straight line student SUG's surface symmetrical tangent Theorem.-The triangle ABC triedral trigonometrical functions vertex vertices whence
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Seite 232 - The square described on the hypothenuse of a right-angled triangle is equivalent to the sum of the squares described on the other two sides.
Seite 41 - The homologous sides of similar triangles are to each other as the square roots of their areas. This theorem is involved in the theorem that the areas of similar triangles are to each other as the squares of their homologous sides.
Seite 203 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Seite 131 - Theorem. — The area of a trapezoid is equal to the product of its altitude...
Seite 217 - If two semicircumferences of great circles intersect on the surface of a hemisphere, the sum of the two opposite triangles thus formed is equivalent to a lune whose angle is that included by the semicircumferences. DEM. — Let the semicircumferences CEB and DEA intersect at E on the surface of the...
Seite 34 - C' (89) (90) (91) (92) (93) 112. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference.
Seite 128 - Theorem — Two triangles are equal when the three sides of the one are respectively equal to the three sides of the other.
Seite 276 - Find the locus of a point the sum of whose distances from two fixed intersecting lines is constant, ie, is equal to a given line.
Seite 96 - The measure of an exterior angle of a triangle is equal to the sum of the measures of the two remote interior angles.
Seite 206 - If two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other, each to each, the two triangles will be equal in all their parts." Axiom 1. "Things which are equal to the same thing, are equal to each other.