A System of Plane and Spherical Trigonometry: To which is Added a Treatise on LogarithmsJ. & J.J. Deighton, 1831 - 330 Seiten |
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Seite xiv
... determine any polyhedron ..... 302 196 . To find the perpendicular altitude of a parallelo- piped ..... 303 197-203 . To find the surface , content , and diagonal , of a pa- rallelopiped .... ... 305 APPENDIX . 12. On the nature of ...
... determine any polyhedron ..... 302 196 . To find the perpendicular altitude of a parallelo- piped ..... 303 197-203 . To find the surface , content , and diagonal , of a pa- rallelopiped .... ... 305 APPENDIX . 12. On the nature of ...
Seite 53
... determination of A from cos A , or log cos A , is involved in the same difficulty . Secondly , the rule for calculating for the additional seconds is not always applicable . For △ tan A sin Δ Α sec A. sec ( A + △ A ) If △ A be ...
... determination of A from cos A , or log cos A , is involved in the same difficulty . Secondly , the rule for calculating for the additional seconds is not always applicable . For △ tan A sin Δ Α sec A. sec ( A + △ A ) If △ A be ...
Seite 55
... determine c thus . α = sin A 134. PROB . α .. c = sin A .. log clog a log sin A + 10 . Given b and c to find a a = √ ( c2 = b2 ) = √ { ( c + b ) ( c = b ) } .. log a = log ( c + b ) + log ( c - b ) . 135. PROB . Given b and c to find ...
... determine c thus . α = sin A 134. PROB . α .. c = sin A .. log clog a log sin A + 10 . Given b and c to find a a = √ ( c2 = b2 ) = √ { ( c + b ) ( c = b ) } .. log a = log ( c + b ) + log ( c - b ) . 135. PROB . Given b and c to find ...
Seite 58
... determined accurately . The second method must not be used when one of the sides other , and the angle A of considerable that case b – c will be very small , and is nearly equal to the magnitude . For in 2 √ bc A therefore sin 6 - C 2 ...
... determined accurately . The second method must not be used when one of the sides other , and the angle A of considerable that case b – c will be very small , and is nearly equal to the magnitude . For in 2 √ bc A therefore sin 6 - C 2 ...
Seite 60
... determined accurately by the sine . 145. PROB . Gain two sides a and b , and an angle A op- posite to one of them to find the remaining side c . First Method . c = b cos A + √ { a2 -b2 ( sin A ) 23 . This formula cannot be easily ...
... determined accurately by the sine . 145. PROB . Gain two sides a and b , and an angle A op- posite to one of them to find the remaining side c . First Method . c = b cos A + √ { a2 -b2 ( sin A ) 23 . This formula cannot be easily ...
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Häufige Begriffe und Wortgruppen
A+B+C a+n ß a+ß a₁ B₁ base C₁ centre chord cosec cot cot diameter equal equations formula four right angles given greater or less hence hypothenuse integer intersection less than 90 Let the sides logarithm loge method Napier's rules nearly negative perpendicular plane angles plane triangle polar triangle pole PROB PROP quadrant quantity R₁ radius unity regular polyhedrons right-angled triangle Similarly sin A sin sin ß sines and cosines small circle solid angle sphere spherical angle spherical polygon spherical triangle ß₁ subtending sum the series suppose tangent trigonometric functions values vers α₁ Απ Δα ηβ π α π π
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Seite 197 - IF two triangles have two sides of the one equal to two sides of the other, each to each ; and have likewise the angles contained by those sides equal to one another ; they shall likewise have their bases, or third sides, equal ; and the two triangles shall be equal ; and their other angles shall be equal, each to each, viz.
Seite 179 - The diameter of a sphere is any straight line which passes through the centre, and is terminated both ways by the superficies of the sphere.
Seite 190 - The sum of the three sides of a spherical triangle is less than the circumference of a great circle. Let ABC be any spherical triangle; produce the sides AB, AU, till they meet again in D.
Seite 191 - THEOREM. The sum of the sides of a spherical polygon is less than the circumference of a great circle.
Seite 181 - ... poles. 751. COR. 2. All great circles of a sphere are equal. 752. COR. 3. Every great circle bisects the sphere. For the two parts into which the sphere is divided can be .so placed that they .will coincide; otherwise there would be points on the surface unequally distant from the centre. 753. COR. 4. Two great circles bisect each other. For the intersection of their planes passes through the centre, and is, therefore, a diameter of each circle. 754.
Seite 252 - A solid angle is that which is made by the meeting of more than two plane angles, which are not in the same plane, in one point. X. ' The tenth definition is omitted for reasons given in the notes.
Seite 189 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Seite 181 - An arc of a great circle may be drawn through any two points on the surface of a sphere.
Seite 45 - Law of Sines — In any triangle, the sides are proportional to the sines of the opposite angles. That is, sin A = sin B...
Seite 9 - The Versed Sine of an arc, is the part of the diameter intercepted between the arc and its sine.