ss+dd

47232, z found.

2

9 + 1011 aa+ee=・

9—10/12/aa—ee=sd=x=46080, x found.

Question 2. Let s and p be given, to find the reft.

That is {

1\a + 6 = s. = 240 } Quære a . e . d . q . z . x2aep=5184

I2 3aa+2ae+ee=SS=

2 x 4 4

4ae = 4p=

57600

20736

345aa — 2ae+ee=SS. 4p=36864
5 w Ea- ·e=√ss-4p=d=192
1+6 720=5+ √ss= -4 P

12 13 14 aa+ee=ss—2p=x=47232
13 15 aa—ee = 5 √ss - 4 p =*=46080

12

Question 3. Suppofe s and q are given, to find the rest.

Question 4. Lets and z be given, to find the rest.

119 + 6 = s. = 240 } Quære a. c. d. p. ?..

2 aa+ee=2.47232

300+2a0+ee=ss

41

4

The reft are found juft as in the 2d Question; the 8 and 10 Steps here being the very fame with the 8 and 10 Steps there.

Question 5. Whens and x are given, to find the reft.

Viz. {

11a+e=s=

240} Quære a.c.d.p.g.zo

2 aα-eex=46080

x

2÷1 34-= ===d, viz. a+e) aa—ee (a—e

Question 6. Suppose d and p are given, to find the reft.

1|a—e=d=192

2ae = p = 5184} Quære a,.s.q.z.x.
3aa2a8fee = d d
2aeeedd

No23aa

2 4 4

4ae=4p

12 13 14 aa+eed d+2p=% 12-1315!aa-ee = d√ d d + 4 p = x

Question 7. Let d and q be given, to find the reft.

Question 8. Suppose d and z given, to find the reft.

Viz. {

2

1a- -e=d= 192} Quære a •

2aa+ee=2=47232

13aa2ae + ce=dd

42 a e=dd

2+4 5aa+2ae+ae=2x-dd

5 w

6a+c=√2z-dds

1+6 72a=d+ √ 2 z―dd

.s.p. q.x.

1

dd

a

·ee = dNo 2:3 ---
d+√2z-dd

=

e

√2z-dd-d

Question