Mathematics: Compiled from the Best Authors and Intended to be the Text-book of the Course of Private Lectures on These Sciences in the University at Cambridge, Band 2Printed at the University Press, by WilliamHilliard, 1801 |
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Seite 18
... parallel to it ; join RH , RG , and draw ON , FB , and QL parallel to RAMK . Now it is evident , that CQ is the sum , and CF the difference , of the sines ; and that GK is the tangent of half the sum AG , and GH the tangent of half the ...
... parallel to it ; join RH , RG , and draw ON , FB , and QL parallel to RAMK . Now it is evident , that CQ is the sum , and CF the difference , of the sines ; and that GK is the tangent of half the sum AG , and GH the tangent of half the ...
Seite 38
... parallel sides by the per- pendicular distance between them , and half the product will be the area . EXAMPLES . * DEMONSTRATION . ABXDE DCX Bn The A ABD is = and the BCD = 2 2 DCX DE or ( because Bn DE ) = ... △ ABD + △ BCD , or 2 ...
... parallel sides by the per- pendicular distance between them , and half the product will be the area . EXAMPLES . * DEMONSTRATION . ABXDE DCX Bn The A ABD is = and the BCD = 2 2 DCX DE or ( because Bn DE ) = ... △ ABD + △ BCD , or 2 ...
Seite 39
... parallel sides are AB 75 , and DC 12:25 , and the perpendicular distance DE or Bn is 154 chains required the area . : 12.25 7'5 19'75 15'4 7900 9875 D C 1975 2 ) 304'150 E 152075 square chains , the answer . 2. How many square feet are ...
... parallel sides are AB 75 , and DC 12:25 , and the perpendicular distance DE or Bn is 154 chains required the area . : 12.25 7'5 19'75 15'4 7900 9875 D C 1975 2 ) 304'150 E 152075 square chains , the answer . 2. How many square feet are ...
Seite 39
... parallel sides by the per- pendicular distance between them , and half the product will be the area . EXAMPLES . * DEMONSTRATION . ABXDE DCX Bn The A ABD is = and the ABCD = 2 2 DCX DE or ( because Bn DE ) = , .. A ABD + a BCD , or 2 ...
... parallel sides by the per- pendicular distance between them , and half the product will be the area . EXAMPLES . * DEMONSTRATION . ABXDE DCX Bn The A ABD is = and the ABCD = 2 2 DCX DE or ( because Bn DE ) = , .. A ABD + a BCD , or 2 ...
Seite 39
... parallel sides are AB 75 , and DC 12:25 , and the perpendicular distance DE or Bn is 15'4 chains required the area . : 12:25 7.5 19'75 15'4 7900 9875 D 12 1975 2 ) 304'150 E 152075 square chains , the answer . 2. How many square feet ...
... parallel sides are AB 75 , and DC 12:25 , and the perpendicular distance DE or Bn is 15'4 chains required the area . : 12:25 7.5 19'75 15'4 7900 9875 D 12 1975 2 ) 304'150 E 152075 square chains , the answer . 2. How many square feet ...
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Häufige Begriffe und Wortgruppen
abscisses ADBA altitude angle answer axes axis azimuth base breadth bung diameter cask centre chord circumference cone conjugate cosine course curve declination departure dial diff difference of latitude difference of longitude distance divided draw drawn ecliptic ellipse equal equinoctial EXAMPLES feet figure find the area find the solidity frustum given head diameter height Hence horizon hour angle hour lines hyperbola hypotenuse intersection latit measure meridian middle latitude miles multiply the sum NOTE oblique circle opposite ordinate parabola parallel of latitude parallel sailing parallelogram perpendicular plane sailing pole primitive PROBLEM PROBLEM projection proportion quadrant radius rectangle Required the area Required the content right ascension right line RULE secant segment side sphere spherical triangle spindle square star station stile subtract sun's tance tang tangent THEOREM transverse trapezium triangle ABC ullage wine gallons yards
Beliebte Passagen
Seite 21 - As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base.
Seite 17 - To find the other side: — as the sum of the two given sides is to their difference, so is the tangent of half the sum of their opposite angles to the tangent of half their difference...
Seite 83 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Seite 328 - The conjugate to any diameter is the line drawn through the centre, and parallel to the tangent of the curve at the vertex of the diameter. So...
Seite 28 - But if the hypothenuse be made radius -, then each leg "will represent the sine of its opposite angle ; namely, the leg AB the sine of the arc AE or angle c, and the leg BC the sine of the arc CD or angle A.
Seite 83 - The axis of a solid is a line drawn from the middle of one end to the middle of the opposite end ; as between the opposite ends of a prism.
Seite 83 - The sphere may be conceived to be formed by the revolution of a semicircle about its diameter, which remains fixed.
Seite 130 - Between these, in a right line, stands an ancient statue, the head whereof is 97 feet from the summit of the higher, and 86 feet from the top of the lower column, and the distance between the...
Seite 205 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 38 - Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area.