« ZurückWeiter »
Now to cast up their Dimensions:
Deductions, make 4 Columns, Br. I Br. 11'Br. 1.Br? asinthe Margin, in
F. IN. the first of which
1334:0 494:0 73:6
624 :0 96:0 28:0 put all the product 1499:4 96:0 | 171:6 i of one Brick and half Thicknefs 3507:4 686:0 273:2 that are not De
273:2 ductions, if there
3234:2 be any of 3 Bricks
457:4 thick put it down
R. twice, &c. then 3693:6 – 13
686 put down all ex. cept deductions that are one Brick 3)1372(457 thick, if two, twice
°17 ard if only half,
as in the Exam. 272)3693.0) (13.
Then add up the firft Column, from the Sum of which fubftract the sum of the Column of Brick and half Deductions; al. so from the Sum of the second Column, fubftract the Sum of the one Brick Deductions, (if there be any :) then reduce the Remainder to the thickness of a Brick and half, and add that result to the Remainder of the first Column, which gives the Con. tent of the Brick work in Feet, and the
Rods are found by dividing it by 272 : As plainly appears in the Operation.
The Art of Surveying and Mea
suring of Land.
First of the Chain.
Ecause Mr Gunter's Chain is moft in use
among Surveyors for measuring of Lines, I shall chiefly insist on that Measure, it being the best in nse for Lands.
This Chain contains in Length 4 Pole or 66 Feet, and is divided into 100 Links, each Link is therefore in Length 722-Inches: If you would turn any Number of Chains into Feet, you must multiply them by 65, as 100 Chains multiplied by 66, makes 6600 Feet; but if you have Links to your Chains to be turned into Feet and parts of Feet, you must fet down the Chains and Links, as if they were one whole Nuinber, and after having multiplyed that Number by 66, cut from the product the two last Figures to the Right Hand, which will be the Hundredth Parts of a Foot, and those on the Left hand the Feet required.
I fet down thus the Multiplicand 15,25
Product in Feet. 1006150 The Product is 1006 i This is fo plain, it needs no other Example.
But now on the other hand, it one thoufand and fix Feet and an halt was given you to reduce into Chains and Links; you muft divide 1000.50 by 66, the Quotient will be 15, 25, viz. 15 Chains 25 Links.
in like manner, if, it had been asked, how many Perches had been contained in 15 Chains 25 Links, you must divide 15, 25 by 25, the Links in cne Perch and the Quotient Answers the Question. 25. 15,25(61. Answer in Perches.
Admit I would know how many Chains are contained in 500 Feet,
38 Anfo 7 Chains 57 Lin.
A T ABL E of Square Measure.
Mile 4014489600 '64000000 278784.00 3097600 15136 10240016400 6401