The Elements of Euclid for the Use of Schools and Colleges: Comprising the First Six Books and Portions of the Eleventh and Twelfth Books : with Notes, an Appendix, and Exercises |
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Seite 24
For the same reason , the exterior angle CEB of the triangle ABE is greater than the angle BAE . But it has been shewn that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC .
For the same reason , the exterior angle CEB of the triangle ABE is greater than the angle BAE . But it has been shewn that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC .
Seite 45
For the same reason the triangle KGC is equal to the triangle KFC . Therefore , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK together with the triangle KGC is equal ...
For the same reason the triangle KGC is equal to the triangle KFC . Therefore , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to the triangle KFC ; the triangle AEK together with the triangle KGC is equal ...
Seite 50
... the two straight lines AC , AG , on the opposite sides of AB , make with it at the point Á the adjacent angles equal to two right angles ; therefore CA is in the same straight line with AG . [ I. 14 . For the same reason , AB and ...
... the two straight lines AC , AG , on the opposite sides of AB , make with it at the point Á the adjacent angles equal to two right angles ; therefore CA is in the same straight line with AG . [ I. 14 . For the same reason , AB and ...
Seite 56
HK For the same reason HF is also a square , and it is on the side HG , which is equal to AC . [ I. 34 . Therefore HF , CK are the squares on AC , CB . And because the complement AG is equal to the complement GE ; [ I. 43 . and that AG ...
HK For the same reason HF is also a square , and it is on the side HG , which is equal to AC . [ I. 34 . Therefore HF , CK are the squares on AC , CB . And because the complement AG is equal to the complement GE ; [ I. 43 . and that AG ...
Seite 62
For the same reason each of the angles CEB , EBC is half a right angle . Therefore the whole angle A EB is a right angle . And because the angle GEF is half a right angle , and the angle EGF a right angle , for it is equal to the ...
For the same reason each of the angles CEB , EBC is half a right angle . Therefore the whole angle A EB is a right angle . And because the angle GEF is half a right angle , and the angle EGF a right angle , for it is equal to the ...
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ABCD AC is equal angle ABC angle BAC Axiom base bisected Book centre chord circle ABC circumference common Construction Corollary Definition demonstration describe a circle described diameter difference divided double drawn equal equal angles equiangular equilateral equimultiples Euclid extremities fall figure fixed formed four fourth given circle given point given straight line greater half Hypothesis inscribed intersect join less magnitudes manner meet multiple namely opposite sides parallel parallelogram pass perpendicular plane polygon PROBLEM produced proportionals PROPOSITION Q.E.D. PROPOSITION quadrilateral radius ratio reason rectangle contained rectilineal figure remaining respectively right angles segment shew shewn sides similar square straight line &c straight line drawn suppose Take taken THEOREM third triangle ABC twice Wherefore whole
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Seite 286 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Seite 30 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Seite 34 - IF a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another; and the exterior angle equal to the interior and opposite upon the same side; and likewise the two interior angles upon the same side together equal to two right angles...
Seite 37 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles.
Seite 12 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Seite 302 - Describe a circle which shall pass through a given point and touch a given straight line and a given circle.
Seite 220 - If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Seite 354 - Prove that the square on any straight line drawn from the vertex of an isosceles triangle to the base, is less than the square on a side of the triangle by the rectangle contained by the segments of the base : and conversely.
Seite 104 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Seite 96 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.