The geometry, by T. S. Davies. Conic sections, by Stephen FenwickJ. Weale, 1853 |
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Seite 2
... circle . 17. A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . 18. A semicircle is the figure contained by a diameter and the part of the circumference cut off by the ...
... circle . 17. A diameter of a circle is a straight line drawn through the centre , and terminated both ways by the circumference . 18. A semicircle is the figure contained by a diameter and the part of the circumference cut off by the ...
Seite 4
... circle BCD , and from the centre B , at the distance BA , describe the circle ACE ; and from the point C , in which the circles cut one another , draw the straight lines ( 1 Post . ) CA , CB , to the points A , B : ABC shall be an ...
... circle BCD , and from the centre B , at the distance BA , describe the circle ACE ; and from the point C , in which the circles cut one another , draw the straight lines ( 1 Post . ) CA , CB , to the points A , B : ABC shall be an ...
Seite 5
... circle CGH , and from the centre D , at the distance DG , describe the circle GKL : AL shall be equal to BC . Because the point B is the centre of the circle CGH , BC is equal ( 15 Def . ) to BG ; B D K H A E And because D is the centre ...
... circle CGH , and from the centre D , at the distance DG , describe the circle GKL : AL shall be equal to BC . Because the point B is the centre of the circle CGH , BC is equal ( 15 Def . ) to BG ; B D K H A E And because D is the centre ...
Seite 10
... circle FDG meeting AB in F , G ; and bisect ( 10. 1. ) FG in H , and join CF , AF CH , CG ; the straight line CH , drawn from the H D given point C , is perpendicular to the given straight line AB . Because FH is equal ( Constr . ) to ...
... circle FDG meeting AB in F , G ; and bisect ( 10. 1. ) FG in H , and join CF , AF CH , CG ; the straight line CH , drawn from the H D given point C , is perpendicular to the given straight line AB . Because FH is equal ( Constr . ) to ...
Seite 15
... circle HLK , and join KF , KG ; the tri- angle KFG has its sides equal to the three straight lines A , B , C. D ... circle DKL , FD is equal straight line A ; therefore circle LKH , GH is equal therefore also GK is equal And FG is equal ...
... circle HLK , and join KF , KG ; the tri- angle KFG has its sides equal to the three straight lines A , B , C. D ... circle DKL , FD is equal straight line A ; therefore circle LKH , GH is equal therefore also GK is equal And FG is equal ...
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Häufige Begriffe und Wortgruppen
ABCD axis base bisected called centre circle circumference coincide common cone construction contained coordinate curve described diameter difference dihedral angles direction distance divided double draw drawn edges ellipse equal equal angles equimultiples extremities faces figure formed four fourth given line given point greater hence horizontal inclination intersection join less likewise magnitudes manner meet method multiple opposite parallel parallelogram pass perpendicular perspective picture plane MN plane of projection position preceding prisms problem produced projector Prop proportional PROPOSITION proved ratio reason rectangle remaining respectively right angles SCHOLIUM segment shown sides similar sphere square straight line surface taken tangent THEOR third touch trace transverse triangle triangle ABC trihedral vertex vertical Whence Wherefore whole
Beliebte Passagen
Seite 19 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Seite 35 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Seite 4 - AB; but things which are equal to the same are equal to one another...
Seite 128 - EQUIANGULAR parallelograms have to one another the ratio which is compounded of the ratios of their sides.* Let AC, CF be equiangular parallelograms, having the angle BCD equal to the angle ECG : the ratio of the parallelogram AC to the parallelogram CF, is the same with the ratio which is compounded of the ratios of their sides. Let BG, CG, be placed in a straight line ; therefore DC and CE are also in a straight line (14.
Seite 8 - If two triangles have two sides of the one equal to two sides of the...
Seite 36 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced...
Seite 21 - BCD, and the other angles to the other angles, (4. 1.) each to each, to which the equal sides are opposite : therefore the angle ACB is equal to the angle CBD ; and because the straight line BC meets the two straight lines AC, BD, and makes the alternate angles ACB, CBD equal to one another, AC is parallel (27. 1 .) to DB ; and it was shown to be equal to it. Therefore straight lines, &c.
Seite 65 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle, the angles which this line makes with the line touching the circle shall be equal to the angles which are in the alternate segments of the circle.
Seite 4 - Magnitudes which coincide with one another, that is, which exactly fill the same space, are equal to one another.
Seite 116 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.