The Elements of Geometry: Or, The First Six Books, with the Eleventh and Twelfth, of Euclid |
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away the common angle A B D. Therefore the remaining angle DBF is equal to the remaining angle BAD ( I. Ax . 3 ) , which is in ... Because ABCD is a quadrilateral figure in a circle , the opposite angles BAD and B CD are equal ( III .
away the common angle A B D. Therefore the remaining angle DBF is equal to the remaining angle BAD ( I. Ax . 3 ) , which is in ... Because ABCD is a quadrilateral figure in a circle , the opposite angles BAD and B CD are equal ( III .
Seite 85
Therefore the remaining angle BAC is equal ( I. 32 and Ax . 1 ) to the remaining angle EDF . Wherefore the triangle A B C is equiangular to the triangle D E F , and it is inscribed in the circle ABC . Q. E. F. Exercise .
Therefore the remaining angle BAC is equal ( I. 32 and Ax . 1 ) to the remaining angle EDF . Wherefore the triangle A B C is equiangular to the triangle D E F , and it is inscribed in the circle ABC . Q. E. F. Exercise .
Seite 130
equal to the angle EDF , in the other ; and the sides about those angles proportionals , that is , B A to A C , as ED to ... AN B CE Because the remaining angle at B is equal to the remaining angle at G ( I. 32 ) , the triangle DGF is ...
equal to the angle EDF , in the other ; and the sides about those angles proportionals , that is , B A to A C , as ED to ... AN B CE Because the remaining angle at B is equal to the remaining angle at G ( I. 32 ) , the triangle DGF is ...
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The Elements of Geometry: Or, the First Six Books, with the Eleventh and ... Euclides Keine Leseprobe verfügbar - 2016 |
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A B C ABCD altitude applied base bisected Book Cassell's centre circle circumference cloth coincide common cone Const contained Corollary cylinder definition demonstration described diagonal diameter divided double draw Edition equal equal angles equiangular equimultiples Exercise extremities fore four fourth given straight line greater half Illustrated inscribed interior join less magnitudes manner meet multiple parallel parallelogram parallelopiped pass perpendicular plane polygon prism PROBLEM produced PROP proportionals proposition proved pyramid ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle sphere square straight lines A B taken THEOREM third triangle triangle ABC twice vertex Vols Wherefore whole