The Elements of Geometry: Or, The First Six Books, with the Eleventh and Twelfth, of Euclid |
Im Buch
Ergebnisse 1-3 von 39
Seite 44
A G is equal ( I. 43 ) to the complement GE ; and AG is the rectangle contained by AC.CB , for GC is equal to CB . Therefore GE is also equal to the rectangle AC.CB. Wherefore A G and GE are equal to twice the rectangle AC.CB.
A G is equal ( I. 43 ) to the complement GE ; and AG is the rectangle contained by AC.CB , for GC is equal to CB . Therefore GE is also equal to the rectangle AC.CB. Wherefore A G and GE are equal to twice the rectangle AC.CB.
Seite 45
is equal to the rectangle A D.B D , together with the square of C D. But the gnomon CM G and LG make up the whole figure CF , which is the square of ... D B , and the square of D B are together equal to the rectangles A C.D B , and CD.
is equal to the rectangle A D.B D , together with the square of C D. But the gnomon CM G and LG make up the whole figure CF , which is the square of ... D B , and the square of D B are together equal to the rectangles A C.D B , and CD.
Seite 153
If from any angle of a triangle a straight line be drawn perpendicular to the base ; the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described ...
If from any angle of a triangle a straight line be drawn perpendicular to the base ; the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described ...
Was andere dazu sagen - Rezension schreiben
Es wurden keine Rezensionen gefunden.
Häufige Begriffe und Wortgruppen
A B C ABCD altitude applied base bisected Book Cassell's centre circle circumference cloth coincide common cone Const contained Corollary cylinder definition demonstration described diagonal diameter divided double draw Edition equal equal angles equiangular equimultiples Exercise extremities fore four fourth given straight line greater half Illustrated inscribed interior join less magnitudes manner meet multiple parallel parallelogram parallelopiped pass perpendicular plane polygon prism PROBLEM produced PROP proportionals proposition proved pyramid ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle sphere square straight lines A B taken THEOREM third touch triangle triangle ABC twice vertex Vols Wherefore whole