The Elements of Geometry: Or, The First Six Books, with the Eleventh and Twelfth, of Euclid |
Im Buch
Ergebnisse 1-3 von 82
Seite 124
As the base B C is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base C Ď , so is the parallelogram E C to the parallelogram C F. Produce B D both ways to the points H and L , and take ...
As the base B C is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base C Ď , so is the parallelogram E C to the parallelogram C F. Produce B D both ways to the points H and L , and take ...
Seite 183
First , let their insisting straight lines A G , EF , LB , and HK ; { CM , NX , OD , and PR be at right angles to their bases . The base EH is to the base N P as CM is to A G. B G F M H L Pl If the base EH be equal to the base NP ...
First , let their insisting straight lines A G , EF , LB , and HK ; { CM , NX , OD , and PR be at right angles to their bases . The base EH is to the base N P as CM is to A G. B G F M H L Pl If the base EH be equal to the base NP ...
Seite 184
base E H is to the base NP , as the altitude of CD is to the altitude of A B. From the points F , B , K , and G ; X , D , R , and M , draw perpendiculars to the planes in which are the bases E H and N P , meeting those planes in the ...
base E H is to the base NP , as the altitude of CD is to the altitude of A B. From the points F , B , K , and G ; X , D , R , and M , draw perpendiculars to the planes in which are the bases E H and N P , meeting those planes in the ...
Was andere dazu sagen - Rezension schreiben
Es wurden keine Rezensionen gefunden.
Häufige Begriffe und Wortgruppen
A B C ABCD altitude applied base bisected Book Cassell's centre circle circumference cloth coincide common cone Const contained Corollary cylinder definition demonstration described diagonal diameter divided double draw Edition equal equal angles equiangular equimultiples Exercise extremities fore four fourth given straight line greater half Illustrated inscribed interior join less magnitudes manner meet multiple parallel parallelogram parallelopiped pass perpendicular plane polygon prism PROBLEM produced PROP proportionals proposition proved pyramid ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle sphere square straight lines A B taken THEOREM third touch triangle triangle ABC twice vertex Vols Wherefore whole