The Elements of Geometry: Or, The First Six Books, with the Eleventh and Twelfth, of Euclid |
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Seite 124
As the base BC is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base CD , so is the parallelogram E C to the parallelogram C F. Produce BD both ways to the points H and L , and take any ...
As the base BC is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base CD , so is the parallelogram E C to the parallelogram C F. Produce BD both ways to the points H and L , and take any ...
Seite 183
First , let their insisting straight lines A G , EF , LB , and HK ; { CM , NX , OD , and PR be at right angles to their bases . The base EH is to the base N P as CM is to A G. B G F M H IL P X If the base E H be equal to the base NP ...
First , let their insisting straight lines A G , EF , LB , and HK ; { CM , NX , OD , and PR be at right angles to their bases . The base EH is to the base N P as CM is to A G. B G F M H IL P X If the base E H be equal to the base NP ...
Seite 196
ABC G. Neither can the base ABC be to the base DE F , as the pyramid A BCG to any solid greater than the pyramid DEFH . For , if it be possible , let this greater solid be Z. Because the base A B C is to the base D E F as the pyramid ...
ABC G. Neither can the base ABC be to the base DE F , as the pyramid A BCG to any solid greater than the pyramid DEFH . For , if it be possible , let this greater solid be Z. Because the base A B C is to the base D E F as the pyramid ...
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The Elements of Geometry: Or, the First Six Books, with the Eleventh and ... Euclides Keine Leseprobe verfügbar - 2016 |
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A B C ABCD altitude applied base bisected Book Cassell's centre circle circumference cloth coincide common cone Const contained Corollary cylinder definition demonstration described diagonal diameter divided double draw Edition equal equal angles equiangular equimultiples Exercise extremities fore four fourth given straight line greater half Illustrated inscribed interior join less magnitudes manner meet multiple parallel parallelogram parallelopiped pass perpendicular plane polygon prism PROBLEM produced PROP proportionals proposition proved pyramid ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle sphere square straight lines A B taken THEOREM third triangle triangle ABC twice vertex Vols Wherefore whole