The Elements of Geometry: Or, The First Six Books, with the Eleventh and Twelfth, of Euclid |
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Seite 85
32 ) to the angle ABC in the alternate segment of the circle . But the angle HAC is equal to ( Const . ) the angle DE F. Therefore also the angle A B C is equal ( I. Ax . 1 ) to DEF . For the same reason , the angle ACB is equal to the ...
32 ) to the angle ABC in the alternate segment of the circle . But the angle HAC is equal to ( Const . ) the angle DE F. Therefore also the angle A B C is equal ( I. Ax . 1 ) to DEF . For the same reason , the angle ACB is equal to the ...
Seite 124
As the base BC is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base CD , so is the parallelogram E C to the parallelogram C F. Produce BD both ways to the points H and L , and take any ...
As the base BC is to the base CD , so is the triangle A B C to the triangle A CD ; and as the base B C is to the base CD , so is the parallelogram E C to the parallelogram C F. Produce BD both ways to the points H and L , and take any ...
Seite 212
Let A B C and D E F be two spheres , of which the diameters are BC and EF . The sphere A B C has to the sphere D E F the triplicate ratio of that which BC has to EF . For , if not , the sphere A B C must have to a sphere either less or ...
Let A B C and D E F be two spheres , of which the diameters are BC and EF . The sphere A B C has to the sphere D E F the triplicate ratio of that which BC has to EF . For , if not , the sphere A B C must have to a sphere either less or ...
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The Elements of Geometry: Or, the First Six Books, with the Eleventh and ... Euclides Keine Leseprobe verfügbar - 2016 |
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A B C ABCD altitude applied base bisected Book Cassell's centre circle circumference cloth coincide common cone Const contained Corollary cylinder definition demonstration described diagonal diameter divided double draw Edition equal equal angles equiangular equimultiples Exercise extremities fore four fourth given straight line greater half Illustrated inscribed interior join less magnitudes manner meet multiple parallel parallelogram parallelopiped pass perpendicular plane polygon prism PROBLEM produced PROP proportionals proposition proved pyramid ratio reason rectangle rectangle contained rectilineal figure remaining angle right angles segment shown sides similar solid solid angle sphere square straight lines A B taken THEOREM third triangle triangle ABC twice vertex Vols Wherefore whole