Dialogues on the First Principles of the Newtonian System, Band 4J. Parker, 1828 - 68 Seiten |
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Seite 2
... prove it . Suppose two tri- angles , of whatever form , to have two sides of the one equal to two sides of the other , each to each ; and the angle contained between those two sides in the one triangle to be equal to that which is ...
... prove it . Suppose two tri- angles , of whatever form , to have two sides of the one equal to two sides of the other , each to each ; and the angle contained between those two sides in the one triangle to be equal to that which is ...
Seite 3
... prove that the angle B is also equal to the angle C. Suppose another triangle DEF , of which the angle D shall be equal to the angle A , the side DE to the side AB , and the side DF to the side AC . Now it follows that the angle E is ...
... prove that the angle B is also equal to the angle C. Suppose another triangle DEF , of which the angle D shall be equal to the angle A , the side DE to the side AB , and the side DF to the side AC . Now it follows that the angle E is ...
Seite 7
... proved by producing one of the sides , as BC , to F , and through C drawing CG parallel to BA ; whence it also becomes evident that the exterior angle ACF , which is formed by producing BC , is equal to both the remote interior angles ...
... proved by producing one of the sides , as BC , to F , and through C drawing CG parallel to BA ; whence it also becomes evident that the exterior angle ACF , which is formed by producing BC , is equal to both the remote interior angles ...
Seite 10
... prove the triangle DEF to be equal to the triangle GHI : in order to which , you must consider that DG is equal to EH , which is equal to FI : DG and FI being therefore equal , by adding to each , or subtracting from each GF , you have ...
... prove the triangle DEF to be equal to the triangle GHI : in order to which , you must consider that DG is equal to EH , which is equal to FI : DG and FI being therefore equal , by adding to each , or subtracting from each GF , you have ...
Seite 15
... proved that CD is parallel to AB . A. One difficulty only occurs to me in this de- monstration . I had supposed , from the first law of motion , that a body in motion would have a tendency to continue in that straight line in which it ...
... proved that CD is parallel to AB . A. One difficulty only occurs to me in this de- monstration . I had supposed , from the first law of motion , that a body in motion would have a tendency to continue in that straight line in which it ...
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Dialogues on the First Principles of the Newtonian System Walter Henry Burton Keine Leseprobe verfügbar - 2009 |
Häufige Begriffe und Wortgruppen
altitude angle ABC angle ACB angle MPH arithmetical progression ascertain attraction bisect centre of gravity centripetal force circle circumference common centre curve curvilinear figure ABC definite diagonal DIALOGUE diameter difference direction divided drawn parallel ellipses equal bases exterior angle fixed point fraction greater hypothenuse indefinitely small portion instance law of motion line BD line be drawn line drawn magnitude monstration moon move multiplying number of equal number of longitudinal number of terms observed orbit parallel lines parallelogram pass perpendicular planets produced Prop proportional proportionate proposition prove quantities of matter quotient radii radius rallel ratio rectangle CD rection represented respectively equal right angles round the earth SBD is equal single impulse space square described square of CD square root straight line sun's supposed supposition thing three angles three sides tion triangle ABC uniform velocity wind XXIII
Beliebte Passagen
Seite 2 - Certainly, it is heaven upon earth, to have a man's mind move in charity, rest in providence, and turn upon the poles of truth.
Seite 2 - If two triangles have two sides of the one equal to two sides of the...
Seite 19 - Equal triangles upon the same base, and upon the same side of it, are between the same parallels.
Seite 37 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Seite 2 - Euclid's, and show by construction that its truth was known to us ; to demonstrate, for example, that the angles at the base of an isosceles triangle are equal...
Seite 10 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Seite 51 - Multiply one half the sum of the first and last terms by the number of terms. Thus, the sum of eight terms of the series whose first term is 3 and last term 38 is 8 x * (3 + 38) = 164.
Seite 19 - Parallelograms on the same base, and between the same parallels, are equal to one another.
Seite 38 - Two parallelograms are similar when they have an angle of the one equal to an angle of the other, and the including sides proportional.
Seite 6 - Then, because the three angles of every triangle are together equal to two right angles, [I.