 | 1854 - 834 Seiten
...product by '01745. Explain what the decimal '01745 represents, and of what ratio it is the value. 5. If the radius of a circle be divided in extreme and mean ratio, prove that the greater segment is equal to the side of an inscribed decagon. C. If the arc of a segment... | |
 | Charles Davies, William Guy Peck - 1855 - 628 Seiten
...alt equal, and the angles also all ccjual. it is a regular decagon, ami may be inscribed in a circle. If the radius of a circle be divided in extreme and mean ratio, that is, 60 that the greater segment shall be a mean proportional between the whole radius and the... | |
 | Adrien Marie Legendre - 1863 - 464 Seiten
...inscribed equilateral triangle is to the radius, as the square root of 3 is to 1. PROPOSITION VI. THEOBEM. If the radius of a circle be divided in extreme and mean ratio, the greater segment will be equal to one side of a regular inscribed decagon. Let ACG be a circle, OA its radius, and AB,... | |
 | Richard Wormell - 1868 - 286 Seiten
...triangle is equiangular and equilateral ; wherefore the chord is equal to the radius. If the radius be divided in extreme and mean ratio, the greater segment is the chord of an arc of 36°. 298. The chord in this case is the side of the inscribed decagon. Let AB be... | |
 | Great Britain. Parliament. House of Commons - 1854 - 826 Seiten
...product by '01745. Explain what the decimal "01745 represents, and of what ratio it is the value. 5. If the radius of a circle be divided in extreme and mean ratio, prove that the greater segment is equal to the side of an inscribed decagon. 6. If the arc of a segment... | |
 | Richard Wormell - 1870 - 304 Seiten
...triangle is equiangular and equilateral; wherefore the chord is equal to the radius. If the radius be divided in extreme and mean ratio, the greater segment is the chord of an arc of 36°. 298. The chord in this case is the side of the inscribed decagon. Let AB be... | |
 | Charles Davies - 1872 - 464 Seiten
...tnscribed equilateral triangle is to the radius, as the square root of 3 is to 1. PROPOSITION VI. THEOREM. If the radius of a circle be divided in extreme and mean ratio, the greater segment will be equal to one side of a regular inscribed decagon. Let ACG be a circle, OA its radius, and AB,... | |
 | Adrien Marie Legendre - 1874 - 500 Seiten
...inscribed equilateral triangle is to the radius, as the square root of 3 is to 1. PROPOSITION VI. THEOKEM. If the radius of a circle be divided in extreme and mean ratio, the greater segment will be equal to one side of a regular inscribed decagon. Let ACG be a circle, OA its radius, and AS,... | |
 | Simon Newcomb - 1881 - 418 Seiten
...the radius OA is divided in extreme and mean ratio at the point P (§ 440). Hence we conclude: 465. If the radius of a circle be divided in extreme and mean ratio, the greater segment will be the chord of one tenth of the circle. Construction. Divide the radius OA of the circle in extreme... | |
 | Simon Newcomb - 1882 - 188 Seiten
...-o~. tan 30° = —^ Vs sec 30° = cos 30° = 4/3' 1/3 Functions of 18°. It is shown in geometry that if the radius of a circle be divided in extreme and mean ratio, the greater segment will be the chord of 36° ; that is, twice the sine of 18°. Putting 1 for the radius and r for the... | |
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If the radius of a circle be divided in extreme and mean ratio, the greater segment is equal to one side of a regular inscribed decagon. 
