Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 Seiten |
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Ergebnisse 1-5 von 13
Seite 21
... coincide with one another , that is , which exactly fill the same space , are equal to one another . 9. The whole is greater than its part . A. The whole is equal to all its parts taken together . ED . B. It is impossible for the same ...
... coincide with one another , that is , which exactly fill the same space , are equal to one another . 9. The whole is greater than its part . A. The whole is equal to all its parts taken together . ED . B. It is impossible for the same ...
Seite 24
... coincide with E , because AB is equal to DE ; and because AB coincides with DE , and the angle A is equal to D , AC will coincide with DF ; wherefore also the point C will coincide with F , because AC is equal to DF . But the point B ...
... coincide with E , because AB is equal to DE ; and because AB coincides with DE , and the angle A is equal to D , AC will coincide with DF ; wherefore also the point C will coincide with F , because AC is equal to DF . But the point B ...
Seite 25
... coincide with EF ; then the side AB will lie on DE , be- cause the angle B is equal to E , and the side AC will lie ... coincides with DE , AC with DF , the angle A with D , and the triangle ABC with DEF . Therefore , if two tri- angles ...
... coincide with EF ; then the side AB will lie on DE , be- cause the angle B is equal to E , and the side AC will lie ... coincides with DE , AC with DF , the angle A with D , and the triangle ABC with DEF . Therefore , if two tri- angles ...
Seite 29
... coincide ; and let BGC represent the triangle DEF in an inverted position . Join AG . Because the sides GB and AB are each equal , by hipothesis , to DE , they are equal to each other ; therefore the triangle ABG is isosceles ...
... coincide ; and let BGC represent the triangle DEF in an inverted position . Join AG . Because the sides GB and AB are each equal , by hipothesis , to DE , they are equal to each other ; therefore the triangle ABG is isosceles ...
Seite 47
... coincide , because they are equal , and the two parals . will stand on the same base and between the same parallels . Therefore they are equal to each other . Therefore , parallelograms & c . Q. E. D. PROPOSITION XXXVII . THEOREM . ED ...
... coincide , because they are equal , and the two parals . will stand on the same base and between the same parallels . Therefore they are equal to each other . Therefore , parallelograms & c . Q. E. D. PROPOSITION XXXVII . THEOREM . ED ...
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Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Keine Leseprobe verfügbar - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Keine Leseprobe verfügbar - 2023 |
Häufige Begriffe und Wortgruppen
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Beliebte Passagen
Seite 36 - Any two sides of a triangle are together greater than the third side.
Seite 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Seite 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Seite 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Seite 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Seite 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Seite 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Seite 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Seite 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.