Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 Seiten |
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Seite 23
... ( Prop . 1 ) . From the centre B , at the distance BC , describe the circle CGH ( 3 Post . ) , and produce DB to G ( 2 Post . ) . From the cen- tre D , at the distance DG , describe the circle GKL , and produce DA to L. AL will be equal ...
... ( Prop . 1 ) . From the centre B , at the distance BC , describe the circle CGH ( 3 Post . ) , and produce DB to G ( 2 Post . ) . From the cen- tre D , at the distance DG , describe the circle GKL , and produce DA to L. AL will be equal ...
Seite 24
... sides of one triangle be equal to two sides of another , each to each , and if the angles contained by those sides be also equal , the triangles will be equal in all respects . PROPOSITION A. THEOREM . This is Prop . 26 . 24 ELEMENTS OF.
... sides of one triangle be equal to two sides of another , each to each , and if the angles contained by those sides be also equal , the triangles will be equal in all respects . PROPOSITION A. THEOREM . This is Prop . 26 . 24 ELEMENTS OF.
Seite 25
... Prop . 26 . If two triangles have two angles of one triangle equal to two angles of the other , each to each , and have also the sides between those angles equal to each other ; then will the other two sides be equal , each to each ...
... Prop . 26 . If two triangles have two angles of one triangle equal to two angles of the other , each to each , and have also the sides between those angles equal to each other ; then will the other two sides be equal , each to each ...
Seite 28
... Prop . V ) ; then because the angle B is equal to C , the side AC is equal to AB ; and because the angle A is equal to C , the side BC is equal to AB . Hence each of the sides AC and BC is equal to AB ; therefore they are equal to each ...
... Prop . V ) ; then because the angle B is equal to C , the side AC is equal to AB ; and because the angle A is equal to C , the side BC is equal to AB . Hence each of the sides AC and BC is equal to AB ; therefore they are equal to each ...
Seite 38
... ( Prop . 22. ) , so that CD be equal to AF CE to AG , and DE to FG . Because DC , CE are equal C AA E G F D B to FA , AG , each to each , and the base DE to FG , the angle C is equal to A ( Prop . 8 ) . Therefore at the given point A , in ...
... ( Prop . 22. ) , so that CD be equal to AF CE to AG , and DE to FG . Because DC , CE are equal C AA E G F D B to FA , AG , each to each , and the base DE to FG , the angle C is equal to A ( Prop . 8 ) . Therefore at the given point A , in ...
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Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Keine Leseprobe verfügbar - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Keine Leseprobe verfügbar - 2023 |
Häufige Begriffe und Wortgruppen
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Beliebte Passagen
Seite 36 - Any two sides of a triangle are together greater than the third side.
Seite 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Seite 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Seite 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Seite 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Seite 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Seite 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Seite 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Seite 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.