The Elements of Euclid for the Use of Schools and CollegesMacmillan, 1872 - 400 Seiten |
Im Buch
Ergebnisse 1-5 von 20
Seite 36
... twice as many right angles as the figure has sides . For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides , by drawing straight lines from a point F within the figure to each of its angles . And ...
... twice as many right angles as the figure has sides . For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides , by drawing straight lines from a point F within the figure to each of its angles . And ...
Seite 55
... twice the rectangle contained by the two parts . Let the straight line AB be divided into any two parts at the point C : the square on AB shall be equal to the squares on AC , CB , together with twice the rectangle con- tained by AC ...
... twice the rectangle contained by the two parts . Let the straight line AB be divided into any two parts at the point C : the square on AB shall be equal to the squares on AC , CB , together with twice the rectangle con- tained by AC ...
Seite 56
... twice the rectangle AC , CB . And HF , CK are the squares on AC , CB . Therefore the four figures HF , CK , AG , GE are equal to the squares on AC , CB , together with twice the rectangle AC , CB . But HF , CK , AG , GE make up the ...
... twice the rectangle AC , CB . And HF , CK are the squares on AC , CB . Therefore the four figures HF , CK , AG , GE are equal to the squares on AC , CB , together with twice the rectangle AC , CB . But HF , CK , AG , GE make up the ...
Seite 59
... twice the rectangle AB , BC is double of AK , for BK is equal to BC . [ II . 4 , Corollary . Therefore the gnomon AKF , together with the square CK , is equal to twice the rectangle AB , BC . To each of these equals add HF , which is ...
... twice the rectangle AB , BC is double of AK , for BK is equal to BC . [ II . 4 , Corollary . Therefore the gnomon AKF , together with the square CK , is equal to twice the rectangle AB , BC . To each of these equals add HF , which is ...
Seite 67
... twice the rectangle BC , CD . Because the straight line BD is divided into two parts at the point C , the square on BD is equal to the squares on BC , CD , and twice the rectangle BC , CD . [ II . 4 . To each of these equals add the ...
... twice the rectangle BC , CD . Because the straight line BD is divided into two parts at the point C , the square on BD is equal to the squares on BC , CD , and twice the rectangle BC , CD . [ II . 4 . To each of these equals add the ...
Andere Ausgaben - Alle anzeigen
Häufige Begriffe und Wortgruppen
ABCD AC is equal angle ABC angle ACB angle BAC angle EDF angles equal Axiom base BC bisects the angle centre chord circle ABC circle described circumference Construction Corollary describe a circle diameter double draw a straight equal angles equal to F equiangular equilateral equimultiples Euclid Euclid's Elements exterior angle given circle given point given straight line gnomon Hypothesis inscribed intersect isosceles triangle less Let ABC magnitudes middle point multiple opposite angles opposite sides parallelogram perpendicular plane polygon produced proportionals PROPOSITION 13 Q.E.D. PROPOSITION quadrilateral radius rectangle contained rectilineal figure remaining angle rhombus right angles right-angled triangle segment shew shewn side BC square on AC straight line &c straight line drawn tangent THEOREM touches the circle triangle ABC triangle DEF twice the rectangle vertex Wherefore