A Royal Road to Geometry: Or, an Easy and Familiar Introduction to the Mathematics. ... By Thomas Malton. ...author, and sold, 1774 - 440 Seiten |
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Seite 3
... Cones . 2. Of other right - angled Parallelopipeds .. 3. Of any Parallelopiped , Prifm or Cylinder whatever . 5. How the Area of a Sphere is ascertained . 24 24 25 26 6. Of the Segment of a Sphere .. 1 7. Of Guaging Veffels , Barrels ...
... Cones . 2. Of other right - angled Parallelopipeds .. 3. Of any Parallelopiped , Prifm or Cylinder whatever . 5. How the Area of a Sphere is ascertained . 24 24 25 26 6. Of the Segment of a Sphere .. 1 7. Of Guaging Veffels , Barrels ...
Seite 7
... Cones . 1. How the Area of a Cube is obtained . 2. Of other right - angled Parallelopipeds . 3. Of any Parallelopiped , Prism or Cylinder whatever . 5. How the Area of a Sphere is ascertained . 23 24 -- 24 25 26 6. Of the Segment of a ...
... Cones . 1. How the Area of a Cube is obtained . 2. Of other right - angled Parallelopipeds . 3. Of any Parallelopiped , Prism or Cylinder whatever . 5. How the Area of a Sphere is ascertained . 23 24 -- 24 25 26 6. Of the Segment of a ...
Seite 81
... Cone or Sphere ; a Right Line perpendi- sular to thofe Planes , if it passes through the Center of one Circle , it will pass through the Centers of them all ; which line is the Axis of the Cylinder , Cone or Sphere . PROBLEM XL . 25 ...
... Cone or Sphere ; a Right Line perpendi- sular to thofe Planes , if it passes through the Center of one Circle , it will pass through the Centers of them all ; which line is the Axis of the Cylinder , Cone or Sphere . PROBLEM XL . 25 ...
Seite 98
... Cone . ( See Def . 15 and 18 , 7th . El . ) PROBLEM I. The Tranfverfe and its Conjugate Diameter being gi- ven , how to determine the Foci , on which an El- lipfis may be described , of the Proportion required . Let X and Z be the ...
... Cone . ( See Def . 15 and 18 , 7th . El . ) PROBLEM I. The Tranfverfe and its Conjugate Diameter being gi- ven , how to determine the Foci , on which an El- lipfis may be described , of the Proportion required . Let X and Z be the ...
Seite 374
... Cone , and Sphere , are confidered ; the Solution of which is truely admirable . It must appear , to all who confider it , before they have gone through this Book ( or fome other on the Subject ) , a matter not merely of difficulty ...
... Cone , and Sphere , are confidered ; the Solution of which is truely admirable . It must appear , to all who confider it , before they have gone through this Book ( or fome other on the Subject ) , a matter not merely of difficulty ...
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Häufige Begriffe und Wortgruppen
ABCD alfo alfo equal alſo Altitudes Angle ABC Area Bafe Baſe becauſe bifected Center Chord Circle circumfcribing Circumference Cone conf confequently Conftruction contains cuting Cylinder defcribe Demonftration Diagonal Diameter divided Divifions draw drawn Ellipfis equal Angles equiangular Euclid external Angle fame manner fame Plane fame Ratio fecond fhall Figure fimilar fince firft firſt fome fquare fubtends fuch fuppofe Geometry given Line greater half Heptagon Ifofceles Inches infcribed interfecting laft lefs manifeft mean Proportional meaſure multiplied neceffary Nonagon oppofite parallel Parallelogram Parallelopiped Pentagon perpendicular pleaſure Point Poligon Prifm Priſm Prob Propofition Pyramid Quantities Radius reaſon Rect Rectangle refpectively Right Angles Right Line Segment Sides Sphere Square Tangent THEOREM thofe thoſe Trapezium Triangle ABC uſe wherefore whofe
Beliebte Passagen
Seite 118 - When you have proved that the three angles of every triangle are equal to two right angles...
Seite 215 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Seite 279 - EG, let fall from a point in the circumference upon the diameter, is a mean proportional between the two segments of the diameter DS, EF (p.
Seite 278 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Seite 180 - From this it is manifest, that if one angle of a triangle be equal to the other two, it is a right angle, because the angle adjacent to it is equal to the same two; and when the adjacent angles are equal, they are right angles.
Seite 242 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D; and read, A is to B as C to D.
Seite 155 - In any triangle, if a line be drawn from the vertex at right angles to the base; the difference of the squares of the sides is equal to the difference of the squares of the segments of the base.
Seite 154 - In any isosceles triangle, the square of one of the equal sides is equal to the square of any straight line drawn from the vertex to the base plus the product of the segments of the base.
Seite 244 - Ratios that are the same to the same ratio, are the same to one another. Let A be to B as C is to D ; and as C to D, so let E be to F.
Seite 118 - Angles, taken together, is equal to Twice as many Right Angles, wanting four, as the Figure has Sides.